If the KOH is in a moderately concentrated aqueous solution, the net reaction can be: 2 Al + 6 H2O => 2 Al(OH)3 + 3 H2. In this instance, the KOH does not undergo any net reaction; instead it catalyzes the reaction between aluminum and water by preventing the solid aluminum from maintaining a passivation layer on its surface.
If the KOH is in a still more concentrated aqueous solution, the reaction can be:
2 Al + 4 KOH => K2Al2O4 + H2.
KOH + NH4CL - KCL + NH3 + H2O = N = OOH + NH4CL - CL + NH3 + H2OO + N4CL - CL + N3 + 2ON4CL - CL + N3 + ON4 - N3 + ON = OBut would only work if you are on about maths, algebrabtw im only 13
The reaction between aluminum (Al) and hydrochloric acid (HCl) is a single replacement reaction. The aluminum metal replaces the hydrogen in hydrochloric acid, producing aluminum chloride and hydrogen gas.
The net ionic equation for the reaction between aluminum acetate and lithium nitrate results in the formation of insoluble aluminum hydroxide, which precipitates out of solution. The net ionic equation is: Al^3+(aq) + 3OH^-(aq) → Al(OH)3(s).
The reaction between aluminum foil and copper(II) sulfate results in the displacement of copper by aluminum, forming aluminum sulfate and copper metal as products. The balanced chemical equation for this reaction is: 3CuSO4 + 2Al -> Al2(SO4)3 + 3Cu.
1. Zn + 2 HCl → ZnCl2 + H22. Treating of aluminum powder with NaOH or KOH solutions.2 Al + 6 H2O + 2 NaOH → 2 NaAl(OH)4 + 3 H2Aluminium2 Al + 6 H2O + 2 OH− → 2 Al(OH)−4 + 3 H2
No, KAlOH4 is not a base. It is a salt resulting from the reaction between potassium hydroxide (KOH) and aluminum hydroxide (Al(OH)3), with the aluminum ion replacing one of the hydrogen ions in KOH.
The reaction between aluminum sulfide (Al₂S₃) and barium (Ba) typically involves a redox reaction where barium reduces aluminum sulfide. This reaction can produce barium sulfide (BaS) and aluminum metal (Al). The overall reaction can be represented as: [ \text{Al}_2\text{S}_3 + 3\text{Ba} \rightarrow 3\text{BaS} + 2\text{Al} ] This results in the formation of a barium sulfide salt and aluminum.
Yes, the given reaction is a combination reaction because two or more reactants combine to form a single product. In this case, aluminum sulfate (Al2(SO4)3) and potassium hydroxide (KOH) react to produce aluminum hydroxide (Al(OH)3) and potassium sulfate (K2SO4).
The equation for the reaction between aluminum hydroxide (Al(OH)3) and water (H2O) is Al(OH)3 + 3H2O → Al(OH)4^- + 3H^+. This reaction results in the formation of the aluminum hydroxide tetrahydroxoaluminate complex ion (Al(OH)4^-) and hydronium ions (H^+).
The reaction of Al and FeCl3 to form Fe and Al2O3 is a redox reaction, specifically a single replacement reaction where Fe gains electrons (reduction) and Al loses electrons (oxidation). The release of energy indicates that it is an exothermic reaction.
This reaction is called "metal-metal exchange reaction".
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The coefficient for Al(s) in the balanced equation depends on the specific reaction you are referring to. For example, in the reaction 2Al(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2(g), the coefficient for Al(s) is 2.
The meaning of 2 Al is two atoms of aluminium.
This depends on the reaction; aluminium is trivalent Al(3+).
Simple methods:- reaction of Zn with HCl- reaction of Al with NaOH
The unbalanced equation: Al + NaNO3 Becomes the balanced equation: Al + 3NaNO3 --> Al(NO3)3 + 3Na for Single Reaplacement.