Cl2 stands for chlorine gas, which is a diatomic molecule composed of two chlorine atoms bonded together. In its natural state, chlorine exists as a greenish-yellow gas with a strong, pungent odor. Chlorine is a highly reactive element commonly used in disinfectants, bleaches, and PVC production.
The balanced equation for the reaction between calcium (Ca) and chlorine (Cl2) to form calcium chloride (CaCl2) is: 2Ca + Cl2 -> 2CaCl2
The balanced equation for the reaction is: 2KF + Cl2 -> 2KCl + F2
The reaction between H2O and Cl2 results in the formation of HCl and HOCl. This reaction occurs when chlorine gas is dissolved in water.
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.
To balance the redox reaction involving H2O, Cl2, P4, POCl3, and HCl, you need to first assign oxidation numbers to each element and then balance the atoms and charges. The balanced equation is: 4 H2O + 6 Cl2 + P4 -> 4 H3PO4 + 6 POCl3 + 4 HCl.
Cl2 (properly written the 2 would be a subscript - but that's tough to do here) represents a diatomic molecule of chlorine. At standard conditions, this is the form pure chlorine takes.
Cl2 is non polar.So there are london bonds.
You start with methane (CH4 ) and chlorine ( Cl2) and react them thus:- CH4 + Cl2 → CH3Cl + HCl CH3Cl + Cl2 → CH2Cl2 + HCl CH2Cl2 + Cl2 → CHCl3 + HCl
If the concentration of Cl2 is decreased, the reaction will shift to the left to try to replace the lost Cl2. This means more C2H4 will react with any remaining Cl2 to form more C2H4Cl2 until a new equilibrium is reached with a lower concentration of Cl2.
2K + Cl2 --> 2KCl
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.
To find the number of moles of Cl2 in 7.1g of chlorine, you need to divide the mass of Cl2 by its molar mass. The molar mass of Cl2 is 70.9 g/mol. Therefore, 7.1g / 70.9 g/mol = 0.1 moles of Cl2.
The balanced equation for the reaction between calcium (Ca) and chlorine (Cl2) to form calcium chloride (CaCl2) is: 2Ca + Cl2 -> 2CaCl2
Cl2
1
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.