NaOH and H2.
This reaction is true for all the group 1 (alkali) metals (Sodium, Lithium, etc.)
Don't try it at home! NaOH is very alkaline and as a result, caustic. It will burn you. Hydrogen gas (H2) is explosive.
:)
H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
It doesn't have an abbreviation per se. Its atomic symbols is Na.NA
OH- + H+ H2O
The balanced chemical equation for the reaction between Na and H2O to form NaOH and H2 is: 2Na + 2H2O → 2NaOH + H2. The equation is balanced as the same number of atoms of each element are present on both sides of the equation.
The reaction between sodium acetate and water is a dissolution process where sodium acetate dissociates into its ions (sodium and acetate) when placed in water. The equation for this process is: CH3COONa + H2O → CH3COO- + Na+ + H2O
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
Na+ + OH- + H+ + Cl- H2O + Na+ + Cl-
H2O. Notice the presence of two elements, H and O. Each of the other three is an element.
The reaction of Na (sodium) with H2O (water) produces NaOH (sodium hydroxide) and H2 (hydrogen gas). So, the equation would be 2Na + 2H2O → 2NaOH + H2.
The net ionic equation for the given reaction would be: H+ + OH- -> H2O
You should get a reddish explosion.
H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
It doesn't have an abbreviation per se. Its atomic symbols is Na.NA
OH- + H+ H2O
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Na+( ion) + Cl- ( ion) + H2O It gets dissociated into ions.
HClO4(aq) + NaOH(aq) → H2O(l) + NaClO4(aq) Ionic Equation: H+ + ClO4- + Na+ + OH- → H2O + Na+ + ClO4-