The evidence to see are
1. has no colour or smell
2. will put out a lit splint
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
The empirical formula for cupric sulfate pentahydrate is CuSO4·5H2O. It consists of one copper (Cu) atom, one sulfur (S) atom, four oxygen (O) atoms, and five water (H2O) molecules.
When heating copper(II) sulfate pentahydrate, the water molecules in the crystal structure are removed, leaving anhydrous copper(II) sulfate. The balanced chemical equation for this reaction is CuSO4·5H2O(s) → CuSO4(s) + 5H2O(g).
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate
Formula: CuSO4.5H2O
Yes, it is
The most common form is the pentahydrate.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
No, copper II sulfate pentahydrate does not sublime. Sublimation is the process of a substance transitioning directly from a solid to a gas without passing through the liquid phase, and copper II sulfate pentahydrate decomposes before it can sublime.
To calculate this, you would need to consider the molar masses of copper(II) sulfate pentahydrate and anhydrous copper(II) sulfate. Copper(II) sulfate pentahydrate has a molar mass that includes water molecules, so you need to determine the molar mass difference between the two compounds. Using this information, you can calculate the amount of copper(II) sulfate pentahydrate needed to obtain 10.0 grams of anhydrous copper(II) sulfate.
The most common hydrated form of copper sulfate is pentahydrate, known as copper(II) sulfate pentahydrate or CuSO4·5H2O. Another hydrated form is trihydrate, with the chemical formula CuSO4·3H2O. These hydrated forms vary in their water content, affecting their physical properties such as color and solubility.
To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
Each molecule of copper(II) sulfate pentahydrate contains one copper atom, one sulfur atom, four oxygen atoms, and five water molecules. So, one molecule of copper(II) sulfate pentahydrate contains a total of 11 atoms.