NaCl is an ionic solid with a high boiling point. Cl2 is held together by weak dispersion forces and is a gas at room temperature. That means Cl2 has already boiled and formed a gas at a temperature lower than room temperature.
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.
NaClO + 2HCl = Cl2 + NaCl +H2O
The balanced chemical equation for the reaction between sodium chloride (NaCl) and elemental fluorine (F2) to form sodium fluoride (NaF) and chlorine gas (Cl2) is: 2 NaCl + F2 -> 2 NaF + Cl2
This is a single replacement reaction where chlorine (Cl2) displaces bromine in sodium bromide (NaBr) to form sodium chloride (NaCl) and bromine gas (Br2).
NaCl has the highest melting point among the compounds listed at 801°C, followed by Cl2 at -101°C, then HCl at -114°C, and finally HF at -83°C.
Boiling point is -34,04 oC.Melting point is - 101,5 oC.
Cl2 is covalent. NaCl is ionic.
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.
Yes, this reaction is possible. Fluorine will displace chlorine from some compounds.
The boiling point in degree Celsius are given below:Na: 883K: 774Si: 2355Ne: -246Silicon has the highest boiling point among the elements given.
The lowest boiling point among CuCl2, HF, and MgCl2 is HF. This is because HF is a molecular compound with weaker intermolecular forces compared to the other two, which are ionic compounds with stronger electrostatic interactions between ions.
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
NaClO + 2HCl = Cl2 + NaCl +H2O
When chlorine gas (Cl2) reacts with dilute sodium hydroxide (NaOH), it forms sodium hypochlorite (NaOCl) and sodium chloride (NaCl), along with water (H2O). The reaction can be represented as Cl2 + 2NaOH -> NaOCl + NaCl + H2O.
The balanced chemical equation for the reaction between sodium chloride (NaCl) and elemental fluorine (F2) to form sodium fluoride (NaF) and chlorine gas (Cl2) is: 2 NaCl + F2 -> 2 NaF + Cl2