PbSO3 is Lead Sulfite, while the 2 at the beginning denotes the amount of that compound there is. For example, there are two Lead Sulfite atoms.
Pb is Lead
SO3 is the polyatomic ion known as sulfite
The chemical compound Pb(SO4)2 is also called lead(IV)sulfate.
Lead sulfite is a chemical compound with the formula PbSO3. It is a pale yellow solid that is not very soluble in water. Lead sulfite is not commonly encountered, but it is used in some chemical research and laboratory studies.
Lead has two oxidation states (+4 and +2). As a result, there are two compounds composed of lead and sulfate: lead(IV) sulfate, which is Pb(SO4)2, and lead(II) sulfate, which is PbSO4.
Helium is number 2 on the Periodic Table, and the number of its mass is 4. So, therefore it has 2 protons, 2 neutrons, and 2 electrons !
The species in question is the sulfate ion, which has a 2- charge. It is thus properly written as SO42-
The ionic compound formed by lead(II) sulfite is PbSO3. Lead(II) ions have a +2 charge, and sulfite ions have a -2 charge. Thus, they combine in a 1:1 ratio to form the compound PbSO3.
PbSO3 is Lead (11) sulfite...In this case..if ide then it is a 3if ite then one higher which is 4if ate then one lower which is 2
Lead(II) sulfite is the ionic compound represented by PbSO3.
The chemical compound Pb(SO4)2 is also called lead(IV)sulfate.
Lead sulfite is a chemical compound with the formula PbSO3. It is a pale yellow solid that is not very soluble in water. Lead sulfite is not commonly encountered, but it is used in some chemical research and laboratory studies.
Lead (II) Sulfite
The chemical formula for lead sulfite is PbSO3.
When sulphite reacts with lead acetate, it forms lead sulphite and lead acetate. The balanced chemical equation for this reaction is: Pb(CH3COO)2 + SO3^2- -> PbSO3 + 2CH3COO-
Oxygen is in this case -2. There are three oxygens in this problem, so the total is -6. Pb's oxidation number is the same as its ionic charge, which is +2. Everything must equal zero out if you add all the numbers together. +2(Pb)+(Sulfur's oxidation number)-6(Oxygen)= 0 -4+(4)=0 Pb=-2 S=+4 O=-2
One atom of lead and one of sulfur for a total of two.
Lead has two oxidation states (+4 and +2). As a result, there are two compounds composed of lead and sulfate: lead(IV) sulfate, which is Pb(SO4)2, and lead(II) sulfate, which is PbSO4.
PbS is not an element, it is a compound.Pb is lead and S is sulfur.The name of this compound is commonly known as Lead Sulfide.