PbSO3 is Lead Sulfite, while the 2 at the beginning denotes the amount of that compound there is. For example, there are two Lead Sulfite atoms.
Pb is Lead
SO3 is the polyatomic ion known as sulfite
lead II sulfite is PbSO3 lead IV sulfite is Pb(SO3)2
The chemical compound Pb(SO4)2 is also called lead(IV)sulfate.
Lead has two oxidation states (+4 and +2). As a result, there are two compounds composed of lead and sulfate: lead(IV) sulfate, which is Pb(SO4)2, and lead(II) sulfate, which is PbSO4.
yes No. Inert elements have an outer electron shell which is exactly filled to capacity. Some of the inert elements are helium, neon, argon, and krypton. These are also referred to as "Nobel Gases". Lead is not one of these. The characteristic of these elements being "Inert", is that except under rare or extreme circumstances, they will not bond with other elements. Lead does not fit this characteristic. To see a list of about 30 common Lead compounds, search (Google, ...) for: common compounds of lead and visit the link titled: "Common Compounds of Lead Pb -- EndMemo" (EndMemo.com) Some of the lead compounds listed there are: Lead Chloride (PbCl2/PbCl4), Lead Oxide (PbO/PbO2), Lead Sulfite (PbSO3), Lead Sulfate (PbSO4).
Helium is number 2 on the Periodic Table, and the number of its mass is 4. So, therefore it has 2 protons, 2 neutrons, and 2 electrons !
PbSO3 is Lead (11) sulfite...In this case..if ide then it is a 3if ite then one higher which is 4if ate then one lower which is 2
lead II sulfite is PbSO3 lead IV sulfite is Pb(SO3)2
Lead (II) Sulfite
The chemical compound Pb(SO4)2 is also called lead(IV)sulfate.
One atom of lead and one of sulfur for a total of two.
Lead has two oxidation states (+4 and +2). As a result, there are two compounds composed of lead and sulfate: lead(IV) sulfate, which is Pb(SO4)2, and lead(II) sulfate, which is PbSO4.
PbS is not an element, it is a compound.Pb is lead and S is sulfur.The name of this compound is commonly known as Lead Sulfide.
Oxygen is in this case -2. There are three oxygens in this problem, so the total is -6. Pb's oxidation number is the same as its ionic charge, which is +2. Everything must equal zero out if you add all the numbers together. +2(Pb)+(Sulfur's oxidation number)-6(Oxygen)= 0 -4+(4)=0 Pb=-2 S=+4 O=-2
The name of this compound is Pb(IV) sulfite or lead disulfite.
yes No. Inert elements have an outer electron shell which is exactly filled to capacity. Some of the inert elements are helium, neon, argon, and krypton. These are also referred to as "Nobel Gases". Lead is not one of these. The characteristic of these elements being "Inert", is that except under rare or extreme circumstances, they will not bond with other elements. Lead does not fit this characteristic. To see a list of about 30 common Lead compounds, search (Google, ...) for: common compounds of lead and visit the link titled: "Common Compounds of Lead Pb -- EndMemo" (EndMemo.com) Some of the lead compounds listed there are: Lead Chloride (PbCl2/PbCl4), Lead Oxide (PbO/PbO2), Lead Sulfite (PbSO3), Lead Sulfate (PbSO4).
(2+2)/(2+2)=1 (2/2)+(2/2)=2 (2*2)-(2/2)=3 (2+2+2)-2=4 (2+2)+(2/2)=5 (2*2*2)-2=6 ((2-.2)/.2)+2=7 2+2+2+2=8 (22/2)+2=9 ((2+2)*2)+2=10 ((2-.2)/.2)+2=11 (2+2+2)*2+=12 (22/2)+2=13 (2/.2)+(2+2)=14 2+(2/2)/.2=15 (2+2)*(2+2)=16 ...??????????=17 ((2+2)/.2)-2=18 ((2+2)-.2)/.2=19 22- √(2+2)=20
230.2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2 = 1073741824