Sodium Bromide
Examples: NaCl, NaBr, NaI, NaF, NaNO3, Na2SO4, CH3COONa, Na2CO3, Na2S etc.
2NaCl + F2 -- 2NaF + Cl2
2NaCl + F2 -> 2NaF + Cl2 The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
Sodium Flouride (NaF) :)
Sodium sulfate has Na2SO4 as its chemical formula. This is the anhydrous form (without water), and it is also seen written as Na2SO4 + 10 H2O, which is its decahydrate. Wikipedia has additional information on this idustrial chemical, and a link is provided below so you can surf on over.
Examples: NaCl, NaBr, NaI, NaF, NaNO3, Na2SO4, CH3COONa, Na2CO3, Na2S etc.
Sodium chloride (table salt), Sodium fluoride, Sodium bromide, Sodium Iodide. they are all salts, products of group 1 Alkali metals reacting with group 7 atoms
NaCl has the highest melting point (between NaCl and H2O)
HCl + NaF -> HF + NaCl
2 moles, if you can find the proper catalyst, or set of reactions to complete the reaction.
2NaCl + F2 -- 2NaF + Cl2
F2 + 2 NaCl = 2 NaF + Cl2
NaCl + CaF2 Check solubility rules to see if it even forms a precipate
2NaCl + F2 -> 2NaF + Cl2 The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
No, Na+ is neutral and F- is very weakly basic, not acidic.
Yes, this reaction is possible. Fluorine will displace chlorine from some compounds.
Here are examples of ionic bonds and ionic compounds: NaBr - sodium bromide KBr - potassium bromide NaCl - sodium chloride NaF - sodium fluoride KI - potassium iodide KCl - potassium chloride CaCl2 - calcium chloride K2O - potassium oxide MgO - magnesium oxide You can recognize ionic compounds because they consist of a metal bonded to a nonmetal.