From an experiment I did in my chemistry lab, I got a value of 52.0 kJ. But I have no idea what the "true" Ea is.
When bleach is mixed with potassium iodide, it undergoes a redox reaction. The bleach oxidizes the iodide ions to produce iodine, which can be observed as a brown color. This reaction can be used to test for the presence of bleach in a solution.
When ions are in solution they move about and thus contain a certain amount of energy. In a lattice, ions are 'fixed' and thus it is a lower energy state. Thus, the reaction goes from relatively high energy to a decrease in internal energy. This reduction in energy is exhibited as heat to the surroundings (i.e. exothermic)
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
The chemical reaction is the following: 2 Al + 3 I2--------2 AlI3
When mercuric chloride is mixed with potassium iodide, a white precipitate of mercuric iodide is formed. This reaction is a double displacement reaction where the ions in the two compounds switch partners. Mercury(II) chloride is soluble in water, while potassium iodide is also soluble, so their reaction forms the insoluble mercuric iodide precipitate.
A substance that speeds up a chemical reaction without being consumed is called a catalyst. Catalysts lower the activation energy needed for a reaction to occur, allowing it to proceed faster, but they remain unchanged at the end of the reaction.
When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.
No reaction because the anion is common in both compounds.
Ethyl iodide will undergo an SN2 reaction with potassium acetate to form ethyl acetate and potassium iodide. This reaction involves the substitution of the iodine atom in ethyl iodide with the acetate ion from potassium acetate.
The reaction of 1-bromo-cyclopentane with sodium iodide in acetone is a nucleophilic substitution reaction known as the Finkelstein reaction. In this reaction, the bromine atom is replaced by an iodine atom, resulting in the formation of sodium bromide, sodium iodide, and cyclopentyl iodide.
It's called a catalyst. A catalyst is present during a chemical reaction but does not participate as a reactant or product. A catalyst lowers the reaction's activation energy, making the reaction easier to happen. In the equation for a chemical reaction, the catalyst's formula appears in small notation above the "yield" arrow (format won't let me show you an example.) An example of a catalyst is potassium iodide (KI) speeding up the decomposition of hydrogen peroxide (H2O2).
The reaction between vanadium (III) sulfate (V2(SO4)3) and barium iodide (BaI2) would form barium sulfate (BaSO4) and vanadium (III) iodide (V2I3). This reaction is a double displacement reaction.
The reaction between lead(II) nitrate and sodium iodide is a double replacement reaction. The products of this reaction are lead(II) iodide and sodium nitrate, formed through the exchange of ions.
The reaction between bromine and aqueous strontium iodide is a double displacement reaction. Bromine replaces iodide in strontium iodide, forming strontium bromide and iodine. The balanced chemical equation is: Br2 + SrI2 --> SrBr2 + I2.
The reaction between silver nitrate and potassium iodide forms silver iodide precipitate and potassium nitrate. This reaction is a double displacement reaction where the silver ions from silver nitrate switch places with the potassium ions in potassium iodide.
When sodium iodide is exposed to light, it may undergo a photochemical reaction where it can decompose or form other products. This is because the light energy can excite the molecules in sodium iodide, leading to potential photoreactions.
There is no reaction, because silver iodide is very insoluble.