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the produc of the reaction is

Mg(s) + CuSO4 (aq)--> MgSO4(aq) + Cu(S)+H2

***NOTE**** the H2 is coming from CuSO4 in a aqueous solution, thus H2O is involved in the reaction. I believe that this would make the precipitate call Copper (II) Oxide. Thus, shouldn't the equation be.....

Mg(s) + CuSO4 (aq) --(H2O)--> MgSO4 (aq) +CuO (s) + H2 (g)

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14y ago

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