If you can't find the dipole moment online then you can get a pretty good approximation using the following method though it is a bit involved. You will need the following two pieces of information before you begin, which I have obtained from Chemistry, The Central Science by Theodore Brown 11e:
Electronegativities (EN) of Se and H: 2.4 and 2.1, respectively.
The bonding radii of the Se and H atoms: 1.16 and 0.37 Ã… (E-10 m), respectively.
To find the dipole moment you must first find the partial charge of the Se and H atoms. This is the amount by which the bonding electrons are shared unequally:
EN(Se)/[EN(Se) + EN(H)] x 2e = amount of the bonding electrons that pertain to Se
= 2.4/(2.4 + 2.1) x 2e = 1.07e → ±0.07e
Se holds a partial charge of -0.07e and H holds a partial charge of +0.07e
e = charge of an electron = 1.602 E-19 coulomb (C)
Next, we find the length of the Se-H bond by simply adding their bonding radii:
(1.16 + 0.37)E-10 m = 1.53E-10 m
Finally, we multiply the separated charge by the distance of separation, where the displacement vector d is directed from the negative to positive charge, to obtain the dipole moment:
μ = q x d = 0.07(1.602E-19 C) x 1.53E-10 m = 1.7E-30 C-m
The molecular dipole moment of H2Se is the sum of the individual Se-H dipole moments. If we place the Se atom at the center of an xy plane, i.e., at the point (0,0), and the two H atoms either above or below the Se atom then we can see that the xcomponents of the two Se-H dipoles cancel each other as their magnitudes are the same, but in an opposite direction. The ycomponents of the two vectors, however, are in the same direction so they add and because they are the same magnitude their sum is simply twice the magnitude of one of them and its direction exactly bisects the molecule.
The magnitude of the y component of one vector is found by taking half of the H-Se-H bond angle, which for a bent molecule is ~104.5°, and multiplying the magnitude of the dipole moment by cosine of half of the angle:
y component = 1.7E-30 C-m x cos(52.25) = 1.0E-30 C-m
Twice this amount gives the net dipole moment of H2Se = 2.0E-30 C-m
Compounds do not have electronegativities, atoms do. The atoms in H2S have electronegativities of H, 2.20 and S, 2.58
0,97D
0.0
The formula for dihydrogen monosulfide is H2S.
H2S is a bent shaped molecule.
Hydrosulfuric acid is H2S. H2S (aq) (H2SO4 is sulfuric acid). The acids with "hydro" at the start of their names are all derived from dissolved gases, e.g. hydrochloric acid is aqueous hydrogen chloride, hydrocyanic acid is aqueous hydrogen cyanide etc.
Why did water and H2S look alike?
H2S and NO2H2sNO2-
no, the electronegativity of sulphur is to small
It varies, dependent on the molecule. H2S ( Hydrogen sulphide ( -2) S ( sulphur) is (0) SO2 ( sulphurt dioxide is (4) SO3 ( sulphur trioxide is (6) These are the various oxidation state numbers. On the Pauling scale of electronegativity the value is 2.5
H2S 63.1 g H2S * 1 mol H2S / 34.076 g H2S = 1.85 mol H2S
The formula for dihydrogen monosulfide is H2S.
H2S = hydrogen sulphide
No, H2S is hydrosulfuric acid. Sulfuric acid is H2SO4
H2O, as the difference in electronegativity between hydrogen and oxygen is the largest (among the options given: SO3 , SO3-- , NH4+, H2O)
The formula for dihydrogen sulfide, or just hydrogen sulfide, is H2S. A pair of hydrogen atoms are bonded to a sulfur atom to make up this toxic compound. A link can be found below for more information.
H2S is a polar compound.It is not ionic.
H2S is a bent shaped molecule.
Add an acid to Na2S.It will emit H2S.
H2S has two lone pairs.So it is bent.