What is the electronegativity of H2S?

Answer 1

If you can't find the dipole moment online then you can get a pretty good approximation using the following method though it is a bit involved. You will need the following two pieces of information before you begin, which I have obtained from Chemistry, The Central Science by Theodore Brown 11e:

Electronegativities (EN) of Se and H: 2.4 and 2.1, respectively.

The bonding radii of the Se and H atoms: 1.16 and 0.37 Ã… (E-10 m), respectively.

To find the dipole moment you must first find the partial charge of the Se and H atoms. This is the amount by which the bonding electrons are shared unequally:

EN(Se)/[EN(Se) + EN(H)] x 2e = amount of the bonding electrons that pertain to Se

= 2.4/(2.4 + 2.1) x 2e = 1.07e → ±0.07e

Se holds a partial charge of -0.07e and H holds a partial charge of +0.07e

e = charge of an electron = 1.602 E-19 coulomb (C)

Next, we find the length of the Se-H bond by simply adding their bonding radii:

(1.16 + 0.37)E-10 m = 1.53E-10 m

Finally, we multiply the separated charge by the distance of separation, where the displacement vector d is directed from the negative to positive charge, to obtain the dipole moment:

μ = q x d = 0.07(1.602E-19 C) x 1.53E-10 m = 1.7E-30 C-m

The molecular dipole moment of H2Se is the sum of the individual Se-H dipole moments. If we place the Se atom at the center of an xy plane, i.e., at the point (0,0), and the two H atoms either above or below the Se atom then we can see that the xcomponents of the two Se-H dipoles cancel each other as their magnitudes are the same, but in an opposite direction. The ycomponents of the two vectors, however, are in the same direction so they add and because they are the same magnitude their sum is simply twice the magnitude of one of them and its direction exactly bisects the molecule.

The magnitude of the y component of one vector is found by taking half of the H-Se-H bond angle, which for a bent molecule is ~104.5°, and multiplying the magnitude of the dipole moment by cosine of half of the angle:

y component = 1.7E-30 C-m x cos(52.25) = 1.0E-30 C-m

Twice this amount gives the net dipole moment of H2Se = 2.0E-30 C-m

Answer 2

The electronegativity of H2S (hydrogen sulfide) is around 2.20. Electronegativity is a measure of an atom's ability to attract and hold onto electrons in a chemical bond. In the case of H2S, the sulfur atom is more electronegative than the hydrogen atoms.

Answer 3

Compounds do not have electronegativities, atoms do. The atoms in H2S have electronegativities of H, 2.20 and S, 2.58

Answer 4

0,97D

Answer 5

0.0