If you can't find the dipole moment online then you can get a pretty good approximation using the following method though it is a bit involved. You will need the following two pieces of information before you begin, which I have obtained from Chemistry, The Central Science by Theodore Brown 11e:
Electronegativities (EN) of Se and H: 2.4 and 2.1, respectively.
The bonding radii of the Se and H atoms: 1.16 and 0.37 Ã… (E-10 m), respectively.
To find the dipole moment you must first find the partial charge of the Se and H atoms. This is the amount by which the bonding electrons are shared unequally:
EN(Se)/[EN(Se) + EN(H)] x 2e = amount of the bonding electrons that pertain to Se
= 2.4/(2.4 + 2.1) x 2e = 1.07e → ±0.07e
Se holds a partial charge of -0.07e and H holds a partial charge of +0.07e
e = charge of an electron = 1.602 E-19 coulomb (C)
Next, we find the length of the Se-H bond by simply adding their bonding radii:
(1.16 + 0.37)E-10 m = 1.53E-10 m
Finally, we multiply the separated charge by the distance of separation, where the displacement vector d is directed from the negative to positive charge, to obtain the dipole moment:
μ = q x d = 0.07(1.602E-19 C) x 1.53E-10 m = 1.7E-30 C-m
The molecular dipole moment of H2Se is the sum of the individual Se-H dipole moments. If we place the Se atom at the center of an xy plane, i.e., at the point (0,0), and the two H atoms either above or below the Se atom then we can see that the xcomponents of the two Se-H dipoles cancel each other as their magnitudes are the same, but in an opposite direction. The ycomponents of the two vectors, however, are in the same direction so they add and because they are the same magnitude their sum is simply twice the magnitude of one of them and its direction exactly bisects the molecule.
The magnitude of the y component of one vector is found by taking half of the H-Se-H bond angle, which for a bent molecule is ~104.5°, and multiplying the magnitude of the dipole moment by cosine of half of the angle:
y component = 1.7E-30 C-m x cos(52.25) = 1.0E-30 C-m
Twice this amount gives the net dipole moment of H2Se = 2.0E-30 C-m
Hydrosulfuric acid is H2S. H2S (aq) (H2SO4 is sulfuric acid). The acids with "hydro" at the start of their names are all derived from dissolved gases, e.g. hydrochloric acid is aqueous hydrogen chloride, hydrocyanic acid is aqueous hydrogen cyanide etc.
H2O (water) is more polar than H2S (hydrogen sulfide) because oxygen is more electronegative than sulfur. This results in a greater difference in electronegativity between the hydrogen and oxygen atoms in water, leading to a more polar molecule.
The chemical formula for hydrogen sulfide is H2S.
When hydrogen sulfide (H2S) burns, it is oxidized to form sulfur dioxide (SO2) gas.
MDEA (methyl diethanolamine) absorbs H2S and CO2 through physical and chemical absorption processes. In physical absorption, H2S and CO2 are dissolved in the MDEA solution due to their solubility in the solvent. In chemical absorption, the H2S and CO2 react with MDEA to form stable compounds, which are then removed from the gas stream.
The type of intermolecular force present in H2S is dipole-dipole forces. H2S molecule has a significant dipole moment due to the difference in electronegativity between sulfur and hydrogen atoms, resulting in the attraction between the δ+ hydrogen and δ- sulfur atoms of neighboring molecules.
It varies, dependent on the molecule. H2S ( Hydrogen sulphide ( -2) S ( sulphur) is (0) SO2 ( sulphurt dioxide is (4) SO3 ( sulphur trioxide is (6) These are the various oxidation state numbers. On the Pauling scale of electronegativity the value is 2.5
Hydrogen sulfide (H2S) exhibits several types of intermolecular forces. The primary force is dipole-dipole interactions, as H2S is a polar molecule due to the electronegativity difference between hydrogen and sulfur. Additionally, it experiences London dispersion forces, which are present in all molecules. However, hydrogen bonding is not significant in H2S compared to water because sulfur is less electronegative than oxygen.
H2S (hydrogen sulfide) is a polar molecule due to its bent molecular geometry and the difference in electronegativity between hydrogen and sulfur atoms. This results in a slight separation of charge between the hydrogen and sulfur atoms, making it polar.
H2O is more polar than H2S because oxygen is more electronegative than sulfur, resulting in a greater difference in electronegativity between the hydrogen and oxygen atoms in H2O compared to H2S. This difference creates a stronger dipole moment in H2O, making it more polar overall.
No, H2S is not capable of hydrogen bonding because it does not contain a hydrogen atom bonded directly to a highly electronegative atom (such as nitrogen, oxygen, or fluorine). Hydrogen bonding occurs between molecules with a hydrogen atom bonded to a highly electronegative atom and another electronegative atom.
Yes, hydrogen sulfide (H2S) does have a dipole moment because it is a polar molecule. The electronegativity difference between hydrogen and sulfur causes an uneven distribution of electron density, resulting in a dipole moment.
Add an acid to Na2S.It will emit H2S.
H2S is a polar compound.It is not ionic.
The pH of a solution containing H2S would be acidic, as H2S is a weak acid. The exact pH value would depend on the concentration of H2S in the solution.
Hydrosulfuric acid is H2S. H2S (aq) (H2SO4 is sulfuric acid). The acids with "hydro" at the start of their names are all derived from dissolved gases, e.g. hydrochloric acid is aqueous hydrogen chloride, hydrocyanic acid is aqueous hydrogen cyanide etc.
The formula for hydrosulfuric acid is H2S.