CH-ch-ch-ch-ch-ch-naoh--------------->ch3-oh
CH3-CH(I)-CH2-CH2-CH2-CH3 + CH3-ONa --------> CH3-CH(O-CH3)-CH2-CH2-CH2-CH3 + NaI
The reaction of 1-chlorobutane with sodium ethoxide results in an SN2 reaction, leading to the substitution of the chlorine atom with an ethoxy group. This forms 1-butanol as the main product.
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr
Sodium Hydroxide + Hydrocloric acid --> Sodiumchloride + Water
The balanced chemical equation for the reaction between sodium and fluorine to produce sodium fluoride is: 2 Na + F2 -> 2 NaF This equation is balanced because there are equal numbers of each type of atom on both the reactant and product sides of the equation.
The reaction between 2-iodohexane and sodium methoxide will result in an SN2 substitution reaction. The equation can be represented as: 2-iodohexane + Sodium methoxide → Hexane + Sodium iodide + Methanol
CH3-CH(I)-CH2-CH2-CH2-CH3 + CH3-ONa --------> CH3-CH(O-CH3)-CH2-CH2-CH2-CH3 + NaI
When 2-iodohexane is treated with sodium methoxide, a nucleophilic substitution reaction occurs. The sodium methoxide acts as a nucleophile attacking the carbon atom bearing the iodine, leading to the formation of hexanol and sodium iodide as byproduct. This reaction follows an SN2 mechanism due to the primary nature of the alkyl halide.
The reaction of 1-chlorobutane with sodium ethoxide results in an SN2 reaction, leading to the substitution of the chlorine atom with an ethoxy group. This forms 1-butanol as the main product.
The balanced equation for the formation of sodium bromide from sodium and bromine is: 2 Na + Br2 → 2 NaBr
Sodium reacts with water to form sodium hydroxide and hydrogen. The balanced equation is 2Na + 2H2O --> 2NaOH + H2.
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr
Methoxide is your nucleophile; it will attack the C3 of 2,2-dimethyloxirane (the carbon that is attached to the oxygen, but doesn't have any methyl groups) via backside attack. This will cause the bond between C3 and the oxygen to break, thus releasing the chain and forming the oxide form of 1-methoxy-2-methyl-2-propanol. Since the oxide of this product is more basic than methanol, it will rip the hydrogen off of methanol, which will create the final product and regenerate methoxide.
The reaction equation for water and sodium carbonate is: Na2CO3 + H2O → 2 NaOH + CO2
Sodium fluoride dissolves in water but does not chemically react with water.
Sodium Hydroxide + Hydrocloric acid --> Sodiumchloride + Water
The formula [not equation!] of sodium oxide is Na2O. A possible equation for forming it is 4 Na + O2 -> 2 Na2O.