Helium molecule is mono atomic.
1 mole = 6.023 x 1023 atoms of helium
So, 2.5 moles = 2.5 x 6.023 x 1023 atoms of helium or 15.058 x 1023 atoms of helium
To find the number of moles of helium in the balloon, you need to divide the mass of helium by its molar mass. The molar mass of helium is approximately 4 g/mol. Therefore, 0.46 g of helium is equal to 0.46 g / 4 g/mol = 0.115 mol of helium in the balloon.
4.002602 g/mol
helium = 4 molar mass
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
To find the number of moles in 250g of hydrogen nitrate (HNO3), we first need to determine the molar mass of HNO3. The molar mass of HNO3 is 63.01 g/mol. Then, we can calculate the number of moles by dividing the given mass by the molar mass: 250g / 63.01 g/mol = approximately 3.97 moles of HNO3 molecules.
The molar mass of helium (He) is approximately 4.0026 g/mol. To find the mass of 0.819 mol of helium, you would multiply the number of moles by the molar mass: 0.819 mol * 4.0026 g/mol ≈ 3.28 grams of helium.
Atomic mass = weight in gram / moles = 10 / 2.5 = 4 amu
Helium is 4g/mol, so 6.46g of helium is 6.46/4=1.62 moles He.
To calculate the number of moles, you need to divide the given mass by the molar mass of helium. The molar mass of helium is approximately 4 g/mol. Therefore, the number of moles in 205g of helium would be 205g / 4g/mol = 51.25 mol.
Argon is heavier than oxygen and helium. Argon has an atomic mass of 39.948 g/mol, while oxygen has an atomic mass of 16.00 g/mol and helium has an atomic mass of 4.003 g/mol. Argon is a noble gas that is denser than both oxygen and helium.
To find the number of moles of helium in the balloon, you need to divide the mass of helium by its molar mass. The molar mass of helium is approximately 4 g/mol. Therefore, 0.46 g of helium is equal to 0.46 g / 4 g/mol = 0.115 mol of helium in the balloon.
4 g of He = 1 mole. So, 30.8 g = 7.7 moles
The mass of 43,7 L of helium at STP is 7.8 g.
1 mole of helium weighs 4.0026 g So. 18.8 of helium will weigh 75.25 g
use this formula, n(He)=m(He)/M(molar mass of He) =0.255G/4.OO =0.06375 moles per gram.
Since magnesium and helium do not form elemental molecules, a mole of these elements is the same as a gram atomic mass, which is 24.305 for magnesium and 4.00260 for helium. The gram molecular mass for sucrose is 342.30. Therefore, the mass of: A. 3 moles of magnesium is 72.915 grams; B 1 mole of sucrose (C12H22O11) is 342.30 grams; and C. 10 moles of helium is 40.0260 grams. The largest of these is obviously the single mole of sucrose.
no. If it was, we would have oxygen balloons instead of helium balloons.