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What is the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water?
RMM OF NaOH= 23+16+1= 40g/mol # mol of NaOH= 42/40= 1.05 mol Concentration= mol/dm 1.05 mol=2.3dm3 X mol = 1 dm3 X=(1.05*1)/2.3 X=.04565M
When 80 g of sodium hydroxideNaOH are dissolved in enough water to make 500 mL of solution the molarity of the solution is?
80 gNaOH / 500 mL = (80 gNaOH / 40 gNaOH/molNaOH) / 0.500 L = 2.0 mol / 0.500 L = 4.0 mol/L
What mass of NaOH is contained in 2.5 L of a 0.010 M solution?
The molarity of NaOH solution is 0.010 mol/L. To find the mass, you need to multiply the molarity by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol. Therefore, the mass of NaOH in 2.5 L of 0.010 M solution is 1 g.
When 80g of sodium hydroxide are dissolved in water to make 0.500 of a solution what is the molarity?
The molarity can be calculated by first converting grams of sodium hydroxide to moles, then dividing by the volume of the solution in liters. In this case, the molar mass of NaOH is 40 g/mol. So, 80g is 2 moles. With a volume of 0.5 L, the molarity is 2 moles / 0.500 L = 4 M.
How many moles of sodium hydroxide are required to neutralize 0.20 mol of nitric acid?
Balanced Equation. NaOH + HNO3 >> NaNO3 + H2O Now, Molarity = moles of solute/liters of solution 0.800M HNO3 + mol/2.50L mol of HNO3 = 2 2mol HNO3 (1mol NaOH/1molHNO3 )(39.998g NaOH/1mol NaOH ) = 79.996 grams
What is the molarity of 80g NaOH dissolved in 1L of water?
To find the molarity, we first need to calculate the number of moles of NaOH. The molar mass of NaOH is 40 g/mol (sodium=23g/mol, oxygen=16g/mol, hydrogen=1g/mol). Thus, 80g NaOH is 2 moles (80g / 40g/mol). Given 1L of solution, the molarity is 2 moles / 1 L = 2 M.
What is the molarity of 4 mol of NaOH dissolved in 2L of water?
The molarity can be calculated by dividing the number of moles of solute by the volume of solution in liters. In this case, the molarity would be 2 M (4 mol NaOH / 2 L water).
What is the molarity of 4mol of NaOH dissolved in 2L of water?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
To calculate the molarity, you first need to convert the grams of NaOH to moles using the molar mass of NaOH (40 g/mol). Then, you divide the moles of NaOH by the volume of solution in liters (450 ml = 0.45 L) to get the molarity. Molarity = moles of NaOH / volume of solution in liters Moles of NaOH = 95 g / 40 g/mol = 2.375 mol Molarity = 2.375 mol / 0.45 L = 5.28 M
How much heat is released when 3.600 mol naoh is dissolved in water?
The heat released when 3.600 mol of NaOH is dissolved in water will depend on the enthalpy change of the dissolution process. This value is typically around -44 kJ/mol for NaOH in water. Therefore, the total heat released would be -44 kJ/mol * 3.600 mol = -158.4 kJ.
Dissolve 2 moles of NaOH in 6 kg of water?
To dissolve 2 moles of NaOH in 6 kg of water, you would need to calculate the molarity of the NaOH solution. First, you would find the molar mass of NaOH (40 g/mol) and then divide the moles by the mass of water in kg to find the molarity. This would be approximately 0.33 mol/L.
A solution of NaOH contains 20g of this compound in 2dm3 of this solution . What is molarity of this solution?
This sodium hydroxide solution has a molarity of 0,25.
What is molarity pure water?
Pure water does not have a molarity because it is not a solute dissolved in a solvent. However, under standard conditions, the molarity of pure water is 55.56 mol/L, which corresponds to its concentration of water molecules.
How much NaOH is in 4.7L of a 0.57 M NaOH solution?
To calculate the amount of NaOH in the solution, multiply the volume (4.7 L) by the molarity (0.57 mol/L). Amount of NaOH = Volume (L) x Molarity (mol/L) = 4.7 L x 0.57 mol/L = 2.679 moles of NaOH.
If 24g of table salt dissolved in 2liters of water what is the concentration of salt in the form of a ratio?
Concentration = Molarity = mol/L24 g NaCl = ?? mol NaCl?? mol NaCl/2 L water = ?? M (M is unit of molarity)
What is the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water?
RMM OF NaOH= 23+16+1= 40g/mol # mol of NaOH= 42/40= 1.05 mol Concentration= mol/dm 1.05 mol=2.3dm3 X mol = 1 dm3 X=(1.05*1)/2.3 X=.04565M
What is the molarity 416.48g BaCl2 dissolved in 2 L of water?
To find the molarity, first calculate the number of moles of BaCl2 by dividing the mass by its molar mass (Ba: 137.33 g/mol, Cl: 35.45 g/mol). Then, divide the number of moles by the volume of water in liters to get the molarity. In this case, the molarity of 416.48 g of BaCl2 dissolved in 2 L of water is approximately 3.02 M.
