answersLogoWhite

0

RMM OF NaOH= 23+16+1= 40g/mol

# mol of NaOH= 42/40= 1.05 mol

Concentration= mol/dm

1.05 mol=2.3dm3

X mol = 1 dm3

X=(1.05*1)/2.3

X=.04565M

User Avatar

Wiki User

15y ago

What else can I help you with?

Continue Learning about Earth Science

How many grams of sodium chloride is in 0.40 moles?

Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============


What is the molarity of 250cm3 sodium chloride solution containing 2 moles?

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, there are 2 moles of sodium chloride in 250 cm^3, which is equivalent to 0.25 L. Therefore, the molarity of the solution is 8 M (2 moles / 0.25 L).


How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?

In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.


How many moles of sodium chloride are there in 250 mL of a 1.20 M sodium chloride solution?

To calculate the number of moles in a solution, use the formula: moles = Molarity x Volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (250 mL = 0.25 L). Then, plug the values into the formula: moles = 1.20 mol/L x 0.25 L = 0.30 moles of sodium chloride.


What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?

Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )

Related Questions

The molarity of a 10.0 L aqueous solution that contains 23.4 grams of sodium chloride is?

The first step is to convert the mass of sodium chloride to moles using its molar mass. Then, divide the moles of sodium chloride by the volume of the solution in liters to calculate the molarity.


How many moles of sodium chhloride are present in 22.0 ml of 0.500 m solution?

Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------


What is the molarity when water is added to 2 moles of sodium chloride to make 0.5 liter of solution?

Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.


How many grams of sodium chloride is in 0.40 moles?

Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============


What is the molarity of 250cm3 sodium chloride solution containing 2 moles?

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, there are 2 moles of sodium chloride in 250 cm^3, which is equivalent to 0.25 L. Therefore, the molarity of the solution is 8 M (2 moles / 0.25 L).


How many moles of sodium chloride are in 5.08 L of a 2.36 M solution?

To find the number of moles of sodium chloride, you can multiply the volume of the solution by its molarity. moles = volume (L) * molarity moles = 5.08 L * 2.36 mol/L moles = 11.9928 mol Therefore, there are approximately 11.99 moles of sodium chloride in 5.08 L of a 2.36 M solution.


What is the molarity of 5.60 mol of sodium carbonate in 1500-mL of solution?

Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...


How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?

In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.


What is the molarity of 6.2L of solution if it contains 2.5 moles if sodium chloride?

Molarity means moles per litre. You have to bring the ratio to moles per a litre. So, 2.5 divided by 6.2 is 0.403 molar.


What is the molarity of a 0.75 L solution that contains 9.1 g sodium chloride?

This molarity is 0,207 mol.


How many moles of sodium chloride are there in 250 mL of a 1.20 M sodium chloride solution?

To calculate the number of moles in a solution, use the formula: moles = Molarity x Volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (250 mL = 0.25 L). Then, plug the values into the formula: moles = 1.20 mol/L x 0.25 L = 0.30 moles of sodium chloride.


What is the molarity of sodium borate?

The molarity of sodium borate (Na2B4O7) would depend on the concentration of the solution. To calculate molarity, you would need to know the amount of sodium borate dissolved in a known volume of solvent. Molarity is expressed in moles of solute per liter of solution.