RMM OF NaOH= 23+16+1= 40g/mol
# mol of NaOH= 42/40= 1.05 mol
Concentration= mol/dm
1.05 mol=2.3dm3
X mol = 1 dm3
X=(1.05*1)/2.3
X=.04565M
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, there are 2 moles of sodium chloride in 250 cm^3, which is equivalent to 0.25 L. Therefore, the molarity of the solution is 8 M (2 moles / 0.25 L).
In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.
To calculate the number of moles in a solution, use the formula: moles = Molarity x Volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (250 mL = 0.25 L). Then, plug the values into the formula: moles = 1.20 mol/L x 0.25 L = 0.30 moles of sodium chloride.
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
The first step is to convert the mass of sodium chloride to moles using its molar mass. Then, divide the moles of sodium chloride by the volume of the solution in liters to calculate the molarity.
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, there are 2 moles of sodium chloride in 250 cm^3, which is equivalent to 0.25 L. Therefore, the molarity of the solution is 8 M (2 moles / 0.25 L).
To find the number of moles of sodium chloride, you can multiply the volume of the solution by its molarity. moles = volume (L) * molarity moles = 5.08 L * 2.36 mol/L moles = 11.9928 mol Therefore, there are approximately 11.99 moles of sodium chloride in 5.08 L of a 2.36 M solution.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.
Molarity means moles per litre. You have to bring the ratio to moles per a litre. So, 2.5 divided by 6.2 is 0.403 molar.
This molarity is 0,207 mol.
To calculate the number of moles in a solution, use the formula: moles = Molarity x Volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (250 mL = 0.25 L). Then, plug the values into the formula: moles = 1.20 mol/L x 0.25 L = 0.30 moles of sodium chloride.
The molarity of sodium borate (Na2B4O7) would depend on the concentration of the solution. To calculate molarity, you would need to know the amount of sodium borate dissolved in a known volume of solvent. Molarity is expressed in moles of solute per liter of solution.