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OK, start by working out what the proportions are in one mole; 90.122 x .5221 = 48.044g carbon 90.122 x .1118 = 10.075g hydrogen 90.122 x .3551 = 32.002g oxygen Now, divide the weights by the atomic weight of each element and round off the answer. 48.044 / 12 = 4 carbon 10.075 / 1 = 10 hydrogen 32.002 / 16 = 2 oxygen The molecular formula is therefore C4H10O2 For added points; The only structural possibilities I can see are either the butane diols, dimethoxyethane or ethoxyethanol.

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Q: What is the molecular formula of a compound with .5331 of carbon .1118 of hydrogen and .3551 of oxygen with a molar mass of 90.122 grams per mole?
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