1: RbCl (Rubidium has 1+ charge, and Chlorine has 1-)
There are two chlorine atoms in CaCl2.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
first you find Mr of chlorine which is 17. Then find moles of chlorine which is mass divided by Mr.. 35.5 divided by 17 equals 2.088 (4sf) Finally avogadro constant.. 6x10^23 atoms per mole so multiply that by 2.088. Havent got a calculator so you do it. Think that's right but havent got calculator so check
Two
To convert the number of chloride atoms to mols of chlorine atoms, simply multiply by Avogadro's number. This number is 6.022E23. Note that chlorine typically exists as a diatomic molecule, consisting of two chlorine atoms.
There are 5 chlorine atoms in PCl5.
There are two chlorine atoms in CaCl2.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
To balance the equation Rb(s) + Cl2(g) → RbCl(s), you need to ensure that the number of atoms of each element is the same on both sides. Since Cl2 has two chlorine atoms, you need two rubidium chloride (RbCl) units to balance the chlorine. Therefore, the balanced equation is 2 Rb(s) + Cl2(g) → 2 RbCl(s), making the coefficient for rubidium (Rb) 2.
The number of protons in the nucleus of each atom of chlorine.
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
Phosphorus trichloride (PCl₃) contains three chlorine atoms per molecule. Therefore, in four molecules of phosphorus trichloride, the total number of chlorine atoms is 4 molecules × 3 chlorine atoms/molecule = 12 chlorine atoms. Thus, there are 12 chlorine atoms in four phosphorus trichloride molecules.
To balance the equation Rb(s) + Cl2(g) → RbCl(s), we need to ensure that the number of atoms for each element is the same on both sides. Since one molecule of Cl2 contains two chlorine atoms, we need two rubidium atoms to react with it. Therefore, the balanced equation is 2 Rb(s) + Cl2(g) → 2 RbCl(s), making the coefficient for rubidium (Rb) equal to 2.
Four chlorine atoms are needed to form a covalent compound with carbon by sharing electrons. Carbon can form four covalent bonds, so it can share one electron with each of the four chlorine atoms to achieve a stable octet electron configuration.
There are 6.022 x 10^23 atoms of chlorine in 1.00 mol of chlorine gas, as Avogadro's number tells us that 1 mole of any substance contains that many atoms.
The two isotopes of chlorine are the same in that they have the same number of protons, which is the atomic number. The neutral atoms of each isotope also have the same number of electrons as protons. They differ in the number of neutrons.