I think it is that there is only 1 electron in its outer shell.
Sodium has one electron in its outer ring.
If sodium loses its outer electron, it becomes a positively charged ion known as a sodium cation. This cation is stable and will seek to bond with other atoms or ions to achieve a full outer electron shell.
Sodium is in the third group in the periodic table. It meens that sodium has three shell. First shell - 2 electrons, second shell - 8 electrons, third shell (outer energy level) - 1 electron.
Sodium has one electron in its outer shell, so it tends to lose that electron to achieve a full outer shell. This makes sodium more stable as it follows the octet rule by having a complete outer electron shell with eight electrons.
The sodium atom will lose its outer electron to achieve stability. By losing this electron, it will have a full outer shell, like a noble gas, and become a positively charged sodium ion.
The electron arrangement in a sodium ion (Na+) is similar to neon, as both have a full outer electron shell. Sodium loses one electron to achieve the stable electron configuration of neon (2,8). Argon has a full outer shell with 8 electrons, making it different from both sodium and neon.
The stable electron arrangement of sodium after the 3s sublevel electrons have been removed is the noble gas configuration of neon. Sodium loses one electron to achieve a full outer shell, similar to the electron configuration of the nearest noble gas element.
Yes, the electron arrangement in a sodium ion (Na+) is similar to neon. Both ions have a stable electron configuration with a full outer energy level (valence shell), making them inert and unreactive. Sodium loses one electron to achieve the same electron configuration as neon.
Sodium has one electron in its outer ring.
Argon has the same electron configuration as a sodium ion. Sodium ion has lost 1 electron from its outer shell, making its electronic configuration 2, 8. Argon's electronic configuration is also 2, 8 in its outer shell.
Sodium has one outer ring electron, and chlorine has seven outer ring electrons. Sodium tends to lose its outer electron, while chlorine tends to gain an extra electron to achieve a stable electron configuration.
1 electron which makes it belongs to group 1
None - the electron goes from sodium TO the chlorine.
If sodium loses its outer electron, it becomes a positively charged ion known as a sodium cation. This cation is stable and will seek to bond with other atoms or ions to achieve a full outer electron shell.
No, sodium's outer shell is not stable because it only has one electron in its outer shell. Sodium will readily react with other elements to achieve a stable electron configuration by losing this electron.
Sodium is in the third group in the periodic table. It meens that sodium has three shell. First shell - 2 electrons, second shell - 8 electrons, third shell (outer energy level) - 1 electron.
Sodium has one electron in its outer shell, so it tends to lose that electron to achieve a full outer shell. This makes sodium more stable as it follows the octet rule by having a complete outer electron shell with eight electrons.