3+
The oxidation number of Li in LiNO2 is +1, as it typically has an oxidation number of +1 in its compounds.
In N2O3, the oxidation number of nitrogen (N) is +3 and the oxidation number of oxygen (O) is -2. This is because the overall charge of the compound is zero, and nitrogen typically has a +3 oxidation state in nitrogen oxides.
Nitrogen can exist in oxidation states ranging from -3 to +5. Some common nitrogen compounds with different oxidation states include ammonia (NH3) in the -3 oxidation state, nitric oxide (NO) in the +2 oxidation state, nitrogen dioxide (NO2) in the +4 oxidation state, and nitric acid (HNO3) in the +5 oxidation state.
The oxidation state of nitrogen in LiNO3 is +5. This is because the sum of the oxidation states of all atoms in the compound must equal the charge of the compound, and lithium is always +1 and oxygen is always -2.
This answer is -1.To find this answer:Oxygen has an oxidation number of -2.Hydrogen has an oxidation number of +1, and there are 3 of themyou want to get the oxidation numbers to add up to 0, so it would be neutral.-2 + 3(+1) = +1Now, to get this to equal zero, it means that N has to be -1.
The oxidation number of Li in LiNO2 is +1, as it typically has an oxidation number of +1 in its compounds.
The minimum oxidation number for nitrogen is -3.
The oxidation number of nitrogen in ammonium nitrite (NH4NO2) is +3. In the ammonium ion (NH4+), nitrogen has an oxidation number of -3 and in the nitrite ion (NO2-), nitrogen has an oxidation number of +3.
The oxidation number of nitrogen in N2 is 0 since it is in its elemental form where the oxidation number is always 0.
This compound is lithium nitrite.
The oxidation number of nitrogen in nitrogen dioxide (NO2) is +4. Each oxygen atom in NO2 has an oxidation number of -2, and since the molecule is neutral, the sum of the oxidation numbers must equal zero. Therefore, the oxidation number of nitrogen is calculated as follows: 2(-2) + x = 0, where x represents the oxidation number of nitrogen. Solving for x gives x = +4.
The oxidation number of nitrogen can vary depending on the compound it is in. In most cases, nitrogen has an oxidation number of -3 when it is in its elemental form or in compounds like ammonia (NH3). However, in compounds like nitrate (NO3-), nitrogen has an oxidation number of +5.
The oxidation number of nitrogen in NO is +2. This is because oxygen has an oxidation number of -2, and since the overall charge of NO (nitrogen monoxide) is 0, the nitrogen atom must have an oxidation number of +2 to balance the equation.
The oxidation number of nitrogen in NO2 is +4. Each oxygen atom has an oxidation number of -2, and since the overall charge of NO2 is 0, the nitrogen atom must have an oxidation number of +4 to balance the charges.
The oxidation number of hydrogen in NH3 is +1, and the oxidation number of nitrogen is -3. This is because hydrogen typically has an oxidation number of +1 and in compounds, nitrogen usually has an oxidation number of -3.
The oxidation number of NO, nitrogen oxide, is +3.
The oxidation number of nitrogen in hydrazine (N2H4) is -2. This is because hydrogen usually has an oxidation number of +1, and in this case, since there are two hydrogens bonded to each nitrogen, the total oxidation number for nitrogen must be -2 to balance it out.