The nominal oxidation state of Pb in this compound is + 8/3, because oxygen is taken to have a minus two oxidation state; the four oxygen atoms therefore have a total charge of -8, and the three lead atoms must have a nominal oxidation state of + 8/3 to balance them. This variation from the normal rule that oxidation states must have whole number values arises because in Pb3O4, two-thirds of the lead atoms have an oxidation state of +2 and the remaining one-third of the lead atoms have an oxidation state of +4, thereby providing a total of +8 electric charges from three lead ions.
It has to be Pb(NO3)2 with NaCl as Pb has a +II oxidation state and NO3 has -I oxidation state. The reaction is the following: Pb(NO3)2 +2NaCl ----> PbCl2 + 2NaNO3
lead (IV) ion is Pb4+ ion. Note that Pb4+ is never found as an ion- the (IV) is an oxidation number or oxidation state.
The oxidation state of chloride (Cl) is -1. As a halogen, chloride is usually found with an oxidation state of -1 in most compounds.
The oxidation state of carbon in methanol (CH3OH) is +2. This is because oxygen has an oxidation state of -2 and hydrogen has an oxidation state of +1, so the carbon must have an oxidation state of +2 to balance the charges in the molecule.
Lead has two oxidation states (+4 and +2). As a result, there are two compounds composed of lead and sulfate: lead(IV) sulfate, which is Pb(SO4)2, and lead(II) sulfate, which is PbSO4.
Pb3O4 contains oxygen in the 2- oxidation state. and lead in the 2+ and 4+ oxidation states.
The formula for white lead is 2PbCO3 · Pb(OH)2, for red lead it is Pb3O4, and for sugar of lead it is Pb(C2H3O2)2.
No, Pb is not a transition metal and it has 2 oxidation states
The oxidation state of Pb in PbO2 is +4. In this compound, oxygen is generally assigned an oxidation state of -2 and since there are two oxygen atoms, the total oxidation state contributed by oxygen is -4. To balance the charge for the compound, the lead atom must have an oxidation state of +4.
Assuming the 2 oxidation state of lead. Pb + 2HNO3 --> Pb(NO3)2 + H2
This is oxidation. The Pb ion is going from a +2 oxidation state to a +4 oxidation state, which means it is losing electrons and being oxidized.
O is 2- and there are two of them so Pb would have to be 4+
The oxidation number of Pb in PbH4 is +2. This is because the oxidation number of hydrogen is +1, and since the sum of the oxidation numbers in a neutral compound is zero, the oxidation number of Pb must be +2 to balance the charges.
Assuming the standard 2 oxidation state, Pb(NO3)2
It has to be Pb(NO3)2 with NaCl as Pb has a +II oxidation state and NO3 has -I oxidation state. The reaction is the following: Pb(NO3)2 +2NaCl ----> PbCl2 + 2NaNO3
The oxidation number of carbon in PbCO3 is +4. This can be determined by assigning oxygen an oxidation number of -2 and lead an oxidation number of +2, and then solving for the oxidation number of carbon using the overall charge of the carbonate ion.
The oxidation number for Pb in PbO2 is +4. Oxygen in compounds is typically -2, so with two oxygens, the total oxidation number contributed by oxygen is -4. This means that the oxidation number of Pb must be +4 to balance the charges.