The nominal oxidation state of Pb in this compound is + 8/3, because oxygen is taken to have a minus two oxidation state; the four oxygen atoms therefore have a total charge of -8, and the three lead atoms must have a nominal oxidation state of + 8/3 to balance them. This variation from the normal rule that oxidation states must have whole number values arises because in Pb3O4, two-thirds of the lead atoms have an oxidation state of +2 and the remaining one-third of the lead atoms have an oxidation state of +4, thereby providing a total of +8 electric charges from three lead ions.
It has to be Pb(NO3)2 with NaCl as Pb has a +II oxidation state and NO3 has -I oxidation state. The reaction is the following: Pb(NO3)2 +2NaCl ----> PbCl2 + 2NaNO3
lead (IV) ion is Pb4+ ion. Note that Pb4+ is never found as an ion- the (IV) is an oxidation number or oxidation state.
-2 oxidation state
Mg = +2 oxidation state P = +5 oxidation state O = -2 oxidation state
O = -2 oxidation state P = +5 oxidation state
Pb3O4 contains oxygen in the 2- oxidation state. and lead in the 2+ and 4+ oxidation states.
No, Pb is not a transition metal and it has 2 oxidation states
It has to be Pb(NO3)2 with NaCl as Pb has a +II oxidation state and NO3 has -I oxidation state. The reaction is the following: Pb(NO3)2 +2NaCl ----> PbCl2 + 2NaNO3
Assuming the 2 oxidation state of lead. Pb + 2HNO3 --> Pb(NO3)2 + H2
in Pb3O4 the oxygen has an oxidation number of -2, the average oxidation number is a fraction (+8/3) so this must be a mixed oxidation sate compound. Teh two common Ox numbers of Pb are +2 and +4. the only way to make +8 overall is to have one Pb4+ and two Pb2+ This compound is a lovely red colour and is often called "red lead". Full marks to teacher - this is a tricky question!
Assuming the standard 2 oxidation state, Pb(NO3)2
Pb[OH]2 for white lead, Pb3O4 red lead
O=-2 Pb=x x+(-2)*2=0 x+4-=0 -4+4=0 Pb4-
+4 for Pb and -1 for each hydrogen
It depends on the compound. Lead can have an oxidation state of either 2+ or 4+
The oxidation number of lead (Pb) in the compound PbCl2 has to be what?
lead (IV) ion is Pb4+ ion. Note that Pb4+ is never found as an ion- the (IV) is an oxidation number or oxidation state.