O is 2- and there are two of them so Pb would have to be 4+
The oxidation number for Pb in PbO2 is +4. Oxygen in compounds is typically -2, so with two oxygens, the total oxidation number contributed by oxygen is -4. This means that the oxidation number of Pb must be +4 to balance the charges.
An ionic bond.
The composition of PbO and PbO2 is explained by the different oxidation states of lead. In PbO, lead is in the +2 oxidation state, while in PbO2, lead is in the +4 oxidation state. This difference in oxidation states leads to the formation of the two different oxides with distinct properties.
The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.
Possible valences of plutonium are: +2,3,4,5,6.
The oxidation number for Pb in PbO2 is +4. Oxygen in compounds is typically -2, so with two oxygens, the total oxidation number contributed by oxygen is -4. This means that the oxidation number of Pb must be +4 to balance the charges.
An ionic bond.
The composition of PbO and PbO2 is explained by the different oxidation states of lead. In PbO, lead is in the +2 oxidation state, while in PbO2, lead is in the +4 oxidation state. This difference in oxidation states leads to the formation of the two different oxides with distinct properties.
The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.
Possible valences of plutonium are: +2,3,4,5,6.
PbO2 is a stronger oxidizing agent compared to PbO because PbO2 has a higher oxidation state of +4 for lead, allowing it to accept more electrons during a redox reaction. This makes PbO2 more likely to cause other substances to be oxidized.
The oxidation state of Pb in PbO2 is +4. In this compound, oxygen is generally assigned an oxidation state of -2 and since there are two oxygen atoms, the total oxidation state contributed by oxygen is -4. To balance the charge for the compound, the lead atom must have an oxidation state of +4.
The product for the reaction between PbO2 and O2 is PbO2.
Plumbic oxide, is Lead (IV) oxide. It has the formula of PbO2, which is neutral. However if you wanted to know the oxidation state of the lead, then it is +4.
Formula unit is (molar mass) * (6.0221421*10^23)Molar mass of PbO2 is239.2089 g/molMolar mass of 50.0g of PbO2 is 50/239.2089 g/molFormula unit of PbO2 is ( 50g/239.2089 g/mol) *(6.0221421*10^23)=(0.20902232316606948988938120613405mol) *(6.0221421*10^23units/mol)=1.2587621321781923665883669044087*10^23unitsor approx. 1,26.1023 formula units.
The traditional name for PbO2 is lead dioxide.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.