An ionic bond.
PbO2 is lead(IV) oxide.
Lead dioxide (PbO2) is typically a dark brown or black color.
Lead Dioxide or Lead IV Oxide
PbO2 is a stronger oxidizing agent compared to PbO because PbO2 has a higher oxidation state of +4 for lead, allowing it to accept more electrons during a redox reaction. This makes PbO2 more likely to cause other substances to be oxidized.
2PbS + 3O2 ----> 2PbO + 2SO2
The product for the reaction between PbO2 and O2 is PbO2.
The traditional name for PbO2 is lead dioxide.
Lead dioxide (PbO2) is typically a dark brown or black color.
PbO2 is lead(IV) oxide.
Lead Dioxide or Lead IV Oxide
In the reaction involving PbO2 and Pb2 AsO2, PbO2 acts as an oxidizing agent because lead (Pb) in PbO2 is in the +4 oxidation state. When it is converted to Pb2 AsO2, the lead is reduced to a lower oxidation state, typically +2. Therefore, PbO2 is reduced in this process, while Pb2 AsO2 is oxidized.
PbO2 is a stronger oxidizing agent compared to PbO because PbO2 has a higher oxidation state of +4 for lead, allowing it to accept more electrons during a redox reaction. This makes PbO2 more likely to cause other substances to be oxidized.
2PbS + 3O2 ----> 2PbO + 2SO2
The chemical equation 2 PbO2 → 2 PbO + O2 represents a decomposition reaction. In this reaction, lead(IV) oxide (PbO2) breaks down into lead(II) oxide (PbO) and oxygen gas (O2). Decomposition reactions typically involve a single compound breaking down into two or more products.
The formula for plumbous oxide is PbO.
The balanced chemical equation for the given reaction is: PbO2 + PbO -> 2PbO + O2 Coefficients: 1 PbO2, 1 PbO, 2 PbO, 1 O2.
The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.