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1 millimolar = 0.001 M NaOH ( a base, remember )

- log(0.001 M NaOH)

= 3

14 - 3

= 11 pH

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Can NaOH and pepsin cause digestion?

No is the answer. Sodium hydroxide is is such a strong alkali that it will 'burn' the cells just like acid does. So it is not found in body. Instead you have sodium bi carbonate. But you have very strong acid in stomach. Hydrochloric acid. Imagine acidity go on increasing ten times as you go from 6 to 5 and 5 to 4. And pH in stomach is 1 to 2. (Why does not stomach is 'not' charred at this pH ?) Pepsin works in high acidic pH only and almost stop working at 5.5 pH. So no question of digestion in sodium hydroxide, which is strong alkali with very high pH. If you lower the pH pepsin starts working again.


Do acids have a high or low pH scale?

an acid is on the left side of the scale. that means the low nubers like 1,2,3. bases are on the right side or high numbers like12,13,14. did you knowthat 14 is the highest number it can go ( that I know of).


How many Hydrogen ions does a solution with a pH of 4 have than a solution with a pH of 7?

A solution with a pH of 4 has 1,000 times more hydrogen ions than a solution with a pH of 7. pH is a logarithmic scale, so each decrease of 1 in pH represents a tenfold increase in hydrogen ion concentration.


Charge of amino acid at pH 1?

At pH 1, the amino acid will be fully protonated because the pH is lower than its pKa value. This means that the amino acid will have a positive charge, as the amino group will be protonated.


Which has the greater concentration of hydrogen ions a substance with a pH of 5 or a substance with a pH of 4?

A substance with a pH of 4 has a greater concentration of hydrogen ions compared to a substance with a pH of 5. The pH scale is logarithmic, so each decrease in pH by 1 represents a tenfold increase in hydrogen ion concentration.

Related Questions

Which has higher pH value 1M HCl or 1 M NaOH solution?

THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE


What is the PH of 1 M NaOH?

The pH of 1 M NaOH is around 14. Sodium hydroxide is a strong base that completely dissociates in water to produce hydroxide ions, which results in a highly alkaline solution with a pH at the upper limits of the pH scale.


What is the pH of 0.1m NaOH and 0.05m NaOH?

The pH of 0.1 M NaOH is approximately 13, as NaOH is a strong base that fully dissociates in water to produce hydroxide ions. The pH of 0.05 M NaOH would also be approximately 13, as the concentration of the base does not impact the basicity significantly when dealing with strong bases.


What are the conversions of millimolars?

Millimolar (mM) is a unit of concentration used in chemistry and biology, where 1 millimolar is equal to 0.001 moles per liter (mol/L). To convert from millimolar to molarity, you can multiply the millimolar value by 0.001. For example, 1 millimolar is equivalent to 0.001 molarity.


What is the pH level of naoh?

That depends on it concentration. 1 mole per liter NaOH (=40g/l) has a pH value of 14. 0.1 mole per liter has a pH of 13; 0.01 mole per liter gives pH=12, ...


Prepare 5 M NaOH of pH 12?

To prepare a 5 M NaOH solution, measure out 200 g of NaOH pellets and dissolve them in enough water to make 1 liter of solution. To adjust the pH to 12, you can titrate the solution with a standard acid solution (e.g. HCl) until the desired pH is reached. Remember to wear appropriate safety gear and use a fume hood when working with NaOH.


What is the pH of 0.15 M NaOH?

pH 1 to 2.Sulfuric acid is a strong diprotic acid: [H+] = 2* 0.15 = 0.30 mole/L H+pH = -log 0.30 = 0.52pH 2.


How do you test hydrochloric acid whether it is strong or weak?

What you are doing here is titration. You know you have a solution of HCl, but you do not know how much HCl is in it. For this you use something that can react with HCl (NaOH) and use an indicator to tell you when the reaction is complete. The reaction is pretty simple: HCl + NaOH --> H2O + NaCl You can see here that NaOH and HCl have a 1:1 mol relationship. So, lets find out how many moles of NaOH you used up with concentration = moles/volume 0.10 M NaOH = moles NaOH/ 0.0197 L NaOH solution Remember that M is in moles/L moles NaOH = 0.00197 moles Since you have a 1:1 relationship of NaOH with HCl, the 0.00197 mol applies to HCl as well. The next question works the same way, but backwards. Try doing it yourself if you understood the first part before reading my answer. Find out how many moles of HCl you have so you can find out how much moles of NaOH you need for the neutralization. 0.050 M HCl = n HCl / 0.020 L HCl soln n HCl = 0.001 mol HCl Remeber the 1:1 relationship, which gives you that n NaOH = 0.001 mol. Now all you need is the volume. 0.1 M NaOH = 0.001 mol NaOH/ Volume soln V = 0.01 L = 10 mL


What is molarity poh and pH of 4.50G of NaOH if diluted in up to 750 ml of H2O?

MW NaOH is 23+16+1 = 40. 4.5g in 750ml is 6.0g in 1L. Molarity is 6/40 = 0.15 OH- concentration is 0.15, pOH is -log100.15 = 0.82 H+ concentration is 10-14/0.15 = 6.67x10-13 pH is -log10 6.67x10-13 = 12.18


Calculate the pH at 10 ml titrant in the titration of 50 ml of 1000m acetic acid with 1000m naoh ka1.7510-5?

To calculate the pH at the 10 mL point in the titration of 50 mL of 1 M acetic acid with 1 M NaOH (Ka = 1.75 x 10^-5), we use the Henderson-Hasselbalch equation. At this point, the acetic acid has been partially neutralized by the NaOH. The moles of acetic acid remaining can be calculated using the initial volume and concentration of acetic acid and the volume of NaOH added. Then, use these values in the Henderson-Hasselbalch equation to determine the pH.


What is the role of 1 percent of NaOH in the isolation of RNA?

Sodium hydroxide (NaOH) is used in RNA isolation to disrupt cell membranes and denature proteins. At 1%, NaOH helps to increase pH, facilitating the release of RNA from cells and protecting it from degradation. It also helps to inactivate RNases, enzymes that can degrade RNA.


How many grams of NaOH must be added to 0.250 L of water to form a solution of pH equals 10.0?

a pH=10 solution of NaOH should contain 0,0001 moles of NaOH/liter. (1 mole/liter for pH=14, 0,1 for pH=13, etc.) A mole of NaOH is 40g-s. (Na=23g O=16g H=1g) 0,0001 mole is 0,004gs. You need the amount necessary for a quarter of a liter, so you divide by four. The result is that you need 0,001gs of NaOH. So if you need to make that solution without any precise laboratory equipment, you should make much larger quantities and just measure 0,250 l-s.