a pH=10 solution of NaOH should contain 0,0001 moles of NaOH/liter. (1 mole/liter for pH=14, 0,1 for pH=13, etc.)
A mole of NaOH is 40g-s. (Na=23g O=16g H=1g) 0,0001 mole is 0,004gs.
You need the amount necessary for a quarter of a liter, so you divide by four. The result is that you need 0,001gs of NaOH.
So if you need to make that solution without any precise laboratory equipment, you should make much larger quantities and just measure 0,250 l-s.
After 50 grams of water evaporate, you will be left with 50 grams of water in which the 3.0 grams of salt is dissolved. So, your solution will now contain 3.0 grams of salt dissolved in 50 grams of water.
Thirteen grams of water is the same as thirteen milliliters. So, if thirteen grams of water were added to the beaker, then thirteen milliliters of water were added.
The more concentrated solution is the one containing 18 grams of salt and 90 grams of water. This is because the concentration of the solute (salt) is higher in this solution compared to the solution containing 5 grams of salt and 10 grams of water.
You have 100 grams of pure dextrose and 9 grams of pure sodium chloride added to one liter of distilled water. The solution is sterilized and packed in polypropylene or polyethylene bottles.
An aqueous solution of LiF would consist of lithium ions (Li+) and fluoride ions (F-) dissolved in water. LiF is a soluble ionic compound, so it dissociates into its ions in water. The solution would be colorless and odorless.
The mass of the solution would be the sum of the mass of the sodium chloride and the mass of water. So, the mass of the solution would be 17.8 grams (NaCl) + 217 grams (water) = 234.8 grams.
E) 82.5 grams of water should be added.
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
After 50 grams of water evaporate, you will be left with 50 grams of water in which the 3.0 grams of salt is dissolved. So, your solution will now contain 3.0 grams of salt dissolved in 50 grams of water.
195 grams.
Thirteen grams of water is the same as thirteen milliliters. So, if thirteen grams of water were added to the beaker, then thirteen milliliters of water were added.
This is from the website linked to the left of this answer under Web Links:Solubility in water, g/100 ml at 20°C: 74.5Therefore, in 1 liter, 745.0 grams of CaCl2 will dissolve to make a saturated solution.
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
To make a 10% sugar solution you need to dissolve 10 grams of sugar and bring the volume up to 100 ml
The more concentrated solution is the one containing 18 grams of salt and 90 grams of water. This is because the concentration of the solute (salt) is higher in this solution compared to the solution containing 5 grams of salt and 10 grams of water.
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
For water (this only applies to water): grams = milliliters.