p(x)=-log([x])
So... pH=-log([H+])
pH = 1.4
The pH of a 0.280 M HCl solution is approximately 0.55. This is because HCl is a strong acid that dissociates completely in solution to produce H+ ions, leading to a low pH value.
if its complete dissociation, then the products would be a salt and water, which means the pH is 7 or neutral. OMG, if the pH is currently 4 then [H+] = 1.0 e-4 M (pH = -log[H+]) if you add 0.003 moles then 1.0e-4 M +.003 M = .0031 M (Since the strong acid HCL completely dissociates in aq solution) pH = -log [.0031M] = 2.51
The pH of a 0.10 M HCl solution is approximately 1.0. This is because HCl is a strong acid that ionizes completely in water to form H+ ions, resulting in a high concentration of H+ ions in solution and a low pH.
Adding 6 M HCl (hydrochloric acid) lowers the solution's pH, causing a shift in methyl red's equilibrium towards the red form. This is because methyl red is a pH indicator that changes color from yellow (at a higher pH) to red (at a lower pH). The addition of acid protonates the indicator, resulting in the color change.
The pH of 0.002 M HCl is approximately 2.3 assuming complete dissociation of HCl into H+ and Cl- ions. The calculation involves taking the negative base 10 logarithm of the concentration of H+ ions which is given by the molarity of the acid solution.
The pH of a 6M HCl solution is 0.
The pH of a solution containing 6M HCl is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a 42m HCl solution would be approximately -log(42) = -1.62. This solution is strongly acidic.
The pH of a 0.0001M aqueous solution of HCl is 4. The pH of a solution is calculated using the formula pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. Since HCl is a strong acid that dissociates completely in water, the concentration of H+ ions in a 0.0001M solution of HCl is also 0.0001M.
its PH is 3
The pH of a 0.280 M HCl solution is approximately 0.55. This is because HCl is a strong acid that dissociates completely in solution to produce H+ ions, leading to a low pH value.
The pH of a 0.010 M HCl solution is approximately 2. This is because HCl is a strong acid that completely dissociates in water to form H+ ions, resulting in an acidic solution.
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
The pH of a 0.140 M HCl solution is approximately 0.85. This is because HCl is a strong acid that completely dissociates in water to give H+ ions, resulting in a low pH.
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
Diluting a 0.01N HCl solution ten times would result in a 0.001N HCl solution. Since HCl is a strong acid that fully dissociates in water, the pH of a 0.001N HCl solution would be around 3 (pH = -log[H+]).