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What is the ratio of the mass in grams of magnesium used to the mass in grams of oxygen that reacted?
Wiki User
∙ 10y ago
Balanced Equation: 2Mg + O2 ---> 2MgO
Givens:
15.0 grams Mg
5.00 grams O2
Atomic Mass of O2- 32.0 grams
Atomic mass of Mg- 24.3 grams
Molecular mass- 40.3 MgO
Ratio- 2 moles : 1 mole : 2 mole
First you have to determine the limiting reactant by converting to moles:
15.0 g / (24.3 g) = .617 moles Mg
5.00 g / (32.0 g) = .156 moles O2
Because there is less of the oxygen, it is the limiting reactant and what the rest of the problem will be based on.
For the second part, you are given grams of oxygen and you are converting it to grams of magnesium oxide.
5.00 grams O2 / (32.0 grams O2)
Wiki User
∙ 15y ago
Wiki User
∙ 13y agofirst you get a balance equation 2Mg + O2 -> 2MgO
then you turn grams into moles
50g divide by the mass of Mg
so 50/24.32 = approx. 2.0567
now go from moles of magnesium to moles oxygen
2.0567 mol Mg * (1 mol O2 / 2 mol Mg) = approx. 1.0284 mol O2
but we want grams of Mg, so
1.0284mol O2 * (32g O2/ 1 mol O2) = approx. 32.9 g O2
Wiki User
∙ 10y agoThe balanced equation of the reaction between Mg and O is:
2Mg + O2 --> 2MgO
The ratio of Mg to O2 is 2:1
Atomic mass of Mg : 24g/mol
2Mg = 2(24) = 48g/mol
Molecular mass of O2 : 2(16) = 32g/mol
Ratio of mass Mg to mass O2 = 48:32 = 3:2
Wiki User
∙ 15y agoBalanced Equation: 2Mg + O2 ---> 2MgO
Givens:
15.0 grams Mg
5.00 grams O2
Atomic mass of O2- 32.0 grams
Atomic mass of Mg- 24.3 grams
Molecular mass- 40.3 MgO
Ratio- 2 moles : 1 mole : 2 mole
First you have to determine the limiting reactant by converting to moles:
15.0 g / (24.3 g) = .617 moles Mg
5.00 g / (32.0 g) = .156 moles O2
Because there is less of the oxygen, it is the limiting reactant and what the rest of the problem will be based on.
For the second part, you are given grams of oxygen and you are converting it to grams of magnesium oxide.
5.00 grams O2 / (32.0 grams O2) × (2 moles MgO) × (40.3 grams MgO) = 12.6 grams MgO
Wiki User
∙ 15y agowell according to the Law of Conservation, what ever you start off with, u must end of with, no more, no less. so i would say that you would have 30g of aluminum oxide...
Wiki User
∙ 14y agoUnless there has been a MASSIVE loss of energy in the reaction (as in an explosion, very long burn, or absurdly bright light generation) it should be about 50g (35g + 15g).
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What is the ratio of magnesium to oxygen in magnesium oxide?
The formula is MgO, which represents a ratio of 1:1.
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If the magnesium is not polished, there may be impurities or oxides on the surface that could affect the reported mole ratio of oxygen to magnesium. This could result in a higher reported mole ratio due to the presence of excess oxygen-containing compounds on the surface, leading to an inaccurate measurement of the actual ratio of oxygen to magnesium.
If the burning of the magnesium ribbon was out of control would it affect the mole ratio of oxygen to magnesium?
No. According to the law of definite proportions, the mole ratio will always be the same.
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magnesium oxide is made up of two elements magnesium & oxygen..
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Magnesium oxide (MgO) has one magnesium atom and one oxygen atom per molecule.
The burning magnesium becomes uncontrolled oops how will this procedural error affect the reported mole ratio of nagnesium to oxygen in the analysis?
You will end up having less oxygen because it goes in doubles, and it is considered as flammable, and magnesium wouldn't burn if you didn't trap oxygen inside the magnesium foil. Some of the Magnesium WILL boil away as it burns, but you will end up with less oxidation anyway.
What is the ratio of the ions in magnesium iodide?
Magnesium : Iodine = 1:2
How many grams of magnesium and oxygen react to form 20 g of magnesium oxide?
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.659
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2Mg + O2 ---> 2MgO Magnesium burns in air forming magnesium oxide
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