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The volume of hydrogen and oxygen after electrolysis:

2H20 (l) + Enegry --> 2H2 (g) + O2 (g)

If electrolysis occurs at standard temp and pressure (s.t.p. = 298.15 K ; 1 atm), then:

PV = nRT

For Hydrogen:

(1 atm) * (Xhydrogen) = 2 moles * (0.08206 L * Atm / K * mol) * (298.15 K)

Xhydrogen = 48.9 L of Hydrogen

since there is half as many moles of Oxygen, then there will be half as much gas or:

Xoxygen = 24.45 L of oxygen (the volume of one mole of gas at s.t.p.)

Remember, this is from 2 moles of water, so if you simplify my balanced chemical equation to one mole of water and a fraction of a mole of oxygen, then you need to decrease the volumes of gasses produced by 0.5. Enjoy!

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