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= What percentage of Ca^2+ remains unprecipitated? = A 75.0 mL sample of 1.48×10^−2M Na2SO4(aq) is added to 75.0 mL of 1.22×10^−2M Ca(NO3)2(aq)
what percentage of Ca^2+ remains unprecipitated??
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The atomic mass of calcium, Ca is 40.1. First we calculate the amount in moles of calcium in a 98.5g pure sample.Amount of Ca = 98.5/40.1 = 2.46mol So there are 2.46 moles of Ca (or Ca atoms).
How many moles of calcium are there in 5.00 g of Ca?
Percent CompositionFirst you have to find all the atomic masses of the elements involved in the compound. Then you have to add them up to get the total molecular mass. Take the atomic mass of Ca and divide it by the total mass. Multiply it by 100 and you will get the percent of Ca in any compound of Ca(OH)2. Once you know the percent composition, you can take Ca's percent from the whole sample. Ca: 40.1O: 16.0×2 = 32.0H2: 1.0×2 = 2.0Ca(OH)2: 74.1 grams(40.1 ÷ 74.4) × 100 = 53.9 % of Ca in Ca(OH)253.9 % of 5.00 grams = 2.67 grams of Ca in Ca(OH)2
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The presence of unprecipitated ions in the supernatant may react with subsequent reagents added and obscure the results of tests.
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