= What percentage of Ca^2+ remains unprecipitated? = A 75.0 mL sample of 1.48×10^−2M Na2SO4(aq) is added to 75.0 mL of 1.22×10^−2M Ca(NO3)2(aq)
what percentage of Ca^2+ remains unprecipitated??
No. It changes negligably from the standard ~21% regardless of elevation. (at any elevation you can survive at anyway) :p The actual amount of available oxygen does change, due to a decrease in atmospheric density as elevation increases. For example: at 17,700ft (apparently a common Mt. Everest base camp) the air density is approximately 51% of the density at sea level. So you COULD express it as 51% of ~21%, which would be about 10.71%.
To determine the number of moles of calcium atoms in 98.5 g of Ca, you need to first calculate the molar mass of Ca (40.08 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 98.5 g of Ca is equal to 98.5 g / 40.08 g/mol ≈ 2.46 moles of Ca atoms.
Percent CompositionFirst you have to find all the atomic masses of the elements involved in the compound. Then you have to add them up to get the total molecular mass. Take the atomic mass of Ca and divide it by the total mass. Multiply it by 100 and you will get the percent of Ca in any compound of Ca(OH)2. Once you know the percent composition, you can take Ca's percent from the whole sample. Ca: 40.1O: 16.0×2 = 32.0H2: 1.0×2 = 2.0Ca(OH)2: 74.1 grams(40.1 ÷ 74.4) × 100 = 53.9 % of Ca in Ca(OH)253.9 % of 5.00 grams = 2.67 grams of Ca in Ca(OH)2
Ca(NO3)2 , Calcium nitrate Nitric acid + Calcium hydroxide ----> Calcium Nitrate + Water 2HNO3 + Ca(OH)2 ---> Ca(NO3)2 + 2H2O
The formula for calcium chlorite is Ca(ClO2)2.
As of May, 2009 the percentage was: 41%
0.03
14%
6566
Approximately 88.5% of the quartz remains after three minutes.
To convert from the molar percentage of a compound to the atomic percentage of its elements, you can use the molar mass of each element to calculate the number of moles of each element in one mole of the compound. Then, you can use these values to determine the atomic percentage of each element. For example, in CaO, one mole of CaO contains 1 mole of Ca and 1 mole of O. So, the atomic percentage of Ca would be (molar percentage of CaO) * (molar mass of Ca) / (molar mass of CaO), and similarly for O.
87.5%.
1 %
The percentage of nitrogen remains the same as the amount of oxygen that was used was replaced by the water vapour and carbon dioxide
Reducible interest is interest calculated as a percentage of the amount that remains owing on a loan.
Normally it is 30% or less.
40 g / 56 g X 100%