Ca: 40.1
O: 16.0×2 = 32.0
H2: 1.0×2 = 2.0
Ca(OH)2: 74.1 grams
(40.1 ÷ 74.4) × 100 = 53.9 % of Ca in Ca(OH)2
53.9 % of 5.00 grams = 2.67 grams of Ca in Ca(OH)2
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
To determine the number of moles of calcium atoms in 98.5 g of Ca, you need to first calculate the molar mass of Ca (40.08 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 98.5 g of Ca is equal to 98.5 g / 40.08 g/mol ≈ 2.46 moles of Ca atoms.
For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.40.0 grams Ca / (40.08 grams) = .998 moles Ca
To find the number of moles of nitrate ion in calcium nitrate, first calculate the molar mass of calcium nitrate (Ca(NO3)2). This is 164.09 g/mol. Divide the given mass (5.600 g) by the molar mass to get the number of moles, which is 0.034 moles. Since there are two nitrate ions in one calcium nitrate molecule, multiply the number of moles by 2 to get the number of moles of nitrate ions, which is 0.068 moles.
Calcium hydroxide (Ca(OH)2) has a molar mass of 74g/mol. To find the number of moles in 0.5000g of calcium hydroxide, you divide the 0.5000gCa(OH)2 by 74gCa(OH)2. The answer is 0.006757mol Ca(OH)2 to the nearest significant figure.
425 g calcium (Ca) is equal to 10,604 moles.
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
To find the number of moles in 16.5g of calcium, first determine the molar mass of calcium (Ca), which is approximately 40.08g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 16.5g ÷ 40.08g/mol ≈ 0.411 moles of calcium.
978 g calcium contain 24,4 moles.
There are 0.18 moles of Ca2+ ions in 0.18 moles of CaF2.
156 g calcium is equivalent to 3,89 moles.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
To determine the number of moles of calcium atoms in 45.8 g of Ca, first find the molar mass of calcium (Ca) from the periodic table (40.08 g/mol). Then, divide the given mass by the molar mass of Ca to get the number of moles. In this case, 45.8 g of Ca is equal to 1.14 moles of Ca atoms.
0,688 g calcium is equivalent to 0,017 moles.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.