Ca: 40.1
O: 16.0×2 = 32.0
H2: 1.0×2 = 2.0
Ca(OH)2: 74.1 grams
(40.1 ÷ 74.4) × 100 = 53.9 % of Ca in Ca(OH)2
53.9 % of 5.00 grams = 2.67 grams of Ca in Ca(OH)2
0.5000g Ca(OH)2 (1mol Ca(OH)2/74.096g)(1mol Ca/1mol Ca(OH)2)(6.022 X 10^23/1mol Ca)(1mol Ca/6.022 X 10^23)
= 0.0067 moles of calcium ions
molar mass Ca = 40.078g/mol
5.00g Ca x (1mol/40.078g) = 0.125mol Ca
5.00 grams calcium (1 mole Ca/40.08 grams)
= 0.125 moles calcium
================
0.125 mol Ca
5/40=0.125mol
0.125
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
Ca!
The atomic mass of calcium, Ca is 40.1. First we calculate the amount in moles of calcium in a 98.5g pure sample.Amount of Ca = 98.5/40.1 = 2.46mol So there are 2.46 moles of Ca (or Ca atoms).
For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.40.0 grams Ca / (40.08 grams) = .998 moles Ca
Ca(NO3)2 5.600 grams calcium nitrate ( 1mole Ca(NO3)2/164.1 grams)(2 moles NO3/1 mole Ca(NO3)2) = 6.825 X 10 -2 moles of nitrate ions -----------------------------------------------
425 g calcium (Ca) is equal to 10,604 moles.
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
Calcium, Ca has atomic mass of 40.1Amount of Ca = 16.5/40.1 = 0.411molThere are 0.411 moles of calcium in a 16.5 gram sample.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
978 g calcium contain 24,4 moles.
156 g calcium is equivalent to 3,89 moles.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
0,688 g calcium is equivalent to 0,017 moles.
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
Ca!