The Atomic Mass of the N atom is 14.0. This means that 1 mole of N atoms weighs 14.0g.
Mass of 5.0 moles of N atoms (or 2.5 moles of diatomic nitrogen molecules, N2)
= 5.0 x 14.0
= 70g
The formula of (unhydrated) barium nitrate is Ba(NO3)2. This means, among other things, that each mole contain one mole of barium atoms, two moles of nitrogen atoms, and six moles of oxygen atoms. Thus, the molar mass of this compound is 137.327 + 2(14.007) + 6(15.999) = 261 grams, to three significant digits. 50 moles will then be fifty times this or 1.3 kilograms, to the justified number of significant digits.
The percent composition of N2S2 is 50% nitrogen and 50% sulfur. This is because each molecule of N2S2 contains two nitrogen atoms and two sulfur atoms, and the percentages represent the relative mass contribution of each element to the total mass of the compound.
1. Calculate formula massCalcium carbonate has chemical formula CaCO3.Its formula mass is 40.1 + 12.0 + 3(16.0) = 100.12. Apply formula to calculate number of moles of CaCO3Amount of CaCO3= mass/formula mass= 50/100.1= 0.50mol
There are 1.68 x 10^24 atoms of sulfur in 280g of a 50% H2SO4 solution. This can be calculated by first finding the moles of H2SO4 in the solution, then using the molar ratio to find the moles of sulfur, and finally converting moles to atoms using Avogadro's number.
9 atoms Here is the formula for ammonium nitrate. NH4NO3 This shows there are two nitrogen atoms, 4 hydrogen, and 3 oxygen. So 1 (nitrogen) + 1(nitrogen) + 4(hydrogen) + 3(oxygen) = 9 atoms
The formula of (unhydrated) barium nitrate is Ba(NO3)2. This means, among other things, that each mole contain one mole of barium atoms, two moles of nitrogen atoms, and six moles of oxygen atoms. Thus, the molar mass of this compound is 137.327 + 2(14.007) + 6(15.999) = 261 grams, to three significant digits. 50 moles will then be fifty times this or 1.3 kilograms, to the justified number of significant digits.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 25 mole of CO2 has 25 moles of carbon atoms and 50 moles of oxygen atoms.
The percent composition of N2S2 is 50% nitrogen and 50% sulfur. This is because each molecule of N2S2 contains two nitrogen atoms and two sulfur atoms, and the percentages represent the relative mass contribution of each element to the total mass of the compound.
To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
A silver sample with the same mass as the Earth (5.972 × 10^24 kg) would contain about 1.96 × 10^50 atoms of silver. This amount of silver corresponds to approximately 3.25 × 10^25 moles.
Nitrogen is usually 3% of your mass so when you half your body mass it would be 1.5%
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
A mole (mol) is a unit of measurement used in chemistry to express the amount of substance. Mass over volume refers to the density of a substance, which is the amount of mass per unit volume. Therefore, "mole of mass over volume" is not a standard term in chemistry.
1. Calculate formula massCalcium carbonate has chemical formula CaCO3.Its formula mass is 40.1 + 12.0 + 3(16.0) = 100.12. Apply formula to calculate number of moles of CaCO3Amount of CaCO3= mass/formula mass= 50/100.1= 0.50mol
There are 1.68 x 10^24 atoms of sulfur in 280g of a 50% H2SO4 solution. This can be calculated by first finding the moles of H2SO4 in the solution, then using the molar ratio to find the moles of sulfur, and finally converting moles to atoms using Avogadro's number.
The molar mass of CaCO3 is approximately 100.09 g/mol. Therefore, the mass of 0.5 moles of CaCO3 would be 50.045 g.
To find the mole fraction of oxygen, you first need to calculate the number of moles of each element. The molar mass of nitrogen is 14 g/mol and oxygen is 16 g/mol. Then, divide the moles of oxygen by the total moles of both elements (oxygen + nitrogen) and multiply by 100 to get the mole percentage of oxygen.