The formula of (unhydrated) barium nitrate is Ba(NO3)2. This means, among other things, that each mole contain one mole of barium atoms, two moles of nitrogen atoms, and six moles of oxygen atoms. Thus, the molar mass of this compound is 137.327
+ 2(14.007) + 6(15.999) = 261 grams, to three significant digits. 50 moles will then be fifty times this or 1.3 kilograms, to the justified number of significant digits.
First, we need to find the formula for barium nitrate. Barium's charge is 2+, and nitrate is a 1-. If you criss-cross charges, the resulting formula is Ba(NO3)2. Now that we have the formula, we need to find the atomic mass. Barium has an atomic mass of 137. Nitrate is composed of nitrogen (14.01g) and oxygen (16.00*3 = 48). The atomic mass of nitrate is 62.01. Since there are two NO3 molecules, we multiply by 2 to get 124.02. Finally, we add the barium for a grand total of 261.02. Finally, we set-up our conversion ratios: 432 g Ba(NO3)2/1 * 1 mol/261.02g = 1.66 mols
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
80.043 g/mol
1 mole of Ammonium Nitrate= 80g (R.A.M of compound) Therefore 8g of Ammonium nitrate= 8g/80g= 0.1 mole (moles = mass given over molar mass)
Hydrogen nitrate has a mass of 63.01 g/mol. In order to find the number of moles you divide the grams by the molar mass. 250/63.01 = 3.96 mol.
233.43 g On A+ the answer's 233.4 =]
First, we need to find the formula for barium nitrate. Barium's charge is 2+, and nitrate is a 1-. If you criss-cross charges, the resulting formula is Ba(NO3)2. Now that we have the formula, we need to find the atomic mass. Barium has an atomic mass of 137. Nitrate is composed of nitrogen (14.01g) and oxygen (16.00*3 = 48). The atomic mass of nitrate is 62.01. Since there are two NO3 molecules, we multiply by 2 to get 124.02. Finally, we add the barium for a grand total of 261.02. Finally, we set-up our conversion ratios: 432 g Ba(NO3)2/1 * 1 mol/261.02g = 1.66 mols
The molar mass for anhydrous barium sulfate (BaSO4) is 233.43 g/mol
106
Molar mass of barium hydroxide, Ba(OH)2 = 171.3Amount of barium hydroxide = mass of sample / molar mass = 317.0/171.3 = 1.85mol
169.8731 g/mol
The molar mass of anhydrous iron(II) nitrate is 179,91 g.
The molar mass of potassium nitrate is 101,1032 g.
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
Mercury nitrate has the formula Hg(NO3)2Adding up the atomic mass for all elements present one arrives at a molar mass = 324.7 g/mol
80.043 g/mol
The molar mass of BaF2 is 175.3238064 g/mol