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The Crisscross method is a technique used to determine the formula of ionic compounds, including zinc nitrate. In this method, the charges of the cations and anions are crossed over to become the subscripts for the opposite ion. For zinc nitrate, zinc (Zn) has a +2 charge, while the nitrate ion (NO₃) has a -1 charge. Therefore, the formula for zinc nitrate is derived by taking the 2 from zinc and placing it as a subscript for nitrate, resulting in Zn(NO₃)₂.
6,022 x 1023 atoms/mole. Calcium nitrate = Ca(NO3)2 .There are 1 mole of calcium making 6,022 x 1023 atoms of calcium.There are 2 moles of nitrate-ions and each nitrate-ion is made up of 1 mole nitrogen, and 3 moles of oxygen. Thath means that the nitrate ion in calcium nitrate has 6 moles oxygen and 2 moles of nitrate:Atoms of nitrogen: 6,022 x 1023 moles-1 x 2 moles = 1,2044 x 1024 atomsAtoms of oxygen: 6,022 x 1023 moles-1 x 6 moles = 3,6132 x 1024 atoms
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
To calculate the number of atoms, we need to use Avogadro's number and the molecular weight of zinc. The molar mass of zinc is 65.38 g/mol. First, convert grams to moles: 135 g / 65.38 g/mol = 2.06 moles. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 2.06 moles * 6.022 x 10^23 atoms/mol = 1.24 x 10^24 atoms of zinc.
As shown by the ionic equation of the reaction, Zn (s) + 2 Ag+ (aq) --> 2 Ag (s) + Zn2+ (aq), each mole of zinc produces two moles of silver. Therefore, 1.30 moles of zinc will displace 2.60 moles of silver.
1 mole of silver nitrate produces 1 mole of silver when it reacts to completion. Therefore, 7 moles of silver nitrate will produce 7 moles of silver.
To make 0.1M zinc nitrate solution, you would dissolve the appropriate amount of zinc nitrate (Zn(NO3)2) in a known volume of water. The molarity is calculated by dividing the moles of solute by the volume of solution in liters. Remember to use the molar mass of zinc nitrate to determine the number of moles needed.
Since silver chromate has a 1:1 molar ratio with silver nitrate, 4 moles of silver nitrate will produce 4 moles of silver chromate.
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
For clarity, zinc (II) nitrate would be the preferred name. However, if you just said "zinc nitrate", most chemists would guess you meant that formula; the +1 oxidation state is technically possible for zinc, but zinc (I) compounds are relatively rare.
Since both chloride anions and nitrate anions have a charge of -1, there will be the same number of moles of silver chloride produced as the moles of silver nitrate reacted. (Since both silver nitrate and silver chloride are ionic compounds, it would be preferable to call their "moles" "formula units" instead.)
1 mole of silver nitrate produces 1 mole of silver chloride in a 1:1 ratio according to the balanced chemical equation AgNO3 + NaCl -> AgCl + NaNO3. Therefore, 7 moles of silver nitrate will produce 7 moles of silver chloride.
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
To find the number of moles of nitrate ion in calcium nitrate, first calculate the molar mass of calcium nitrate (Ca(NO3)2). This is 164.09 g/mol. Divide the given mass (5.600 g) by the molar mass to get the number of moles, which is 0.034 moles. Since there are two nitrate ions in one calcium nitrate molecule, multiply the number of moles by 2 to get the number of moles of nitrate ions, which is 0.068 moles.
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
According to the balanced chemical equation, the stoichiometry of the reaction is 1 mole of zinc reacts with 2 moles of hydrochloric acid. Therefore, to react with 2.3 moles of zinc, you would need 4.6 moles of hydrochloric acid (2.3 moles zinc * 2 moles HCl / 1 mole Zn).