You are dealing with density, so the formula is:
D = m/v
Density = Mass ÷ Volume
In the problem, you are given mass (54 g) and density (2.70 g/cm3); so we solve for v (volume).
2.7 = 54 ÷ v
v = 20 cm3
without knowing the units of your density, I'm going to guess candle wax. I think the units are 0.87 plus or minus 0.02g/mL, so I would say Lauric acid which has a density of 0.88g/mL and a melting point of 43 degrees C.
Xe or Xenon has 1 atom in it , Xenon. Xenon has 54 electrons and 54 protons.
The volume that 2.4 moles of chlorine gas would occupy depends on the temperature and pressure of the gas, according to the ideal gas law (PV = nRT). At standard temperature and pressure (STP), which is 0°C and 1 atm pressure, 2.4 moles of chlorine gas would occupy approximately 53.75 liters.
Barium (Ba) has an atomic number of 56, which means it has 56 electrons in a neutral atom. The "2" you mentioned likely refers to the charge on the barium ion (Ba2+), which means it has lost two electrons, resulting in 54 electrons in the Ba2+ ion.
Stoichiometrically:2 Al :=: 3 H2SO4 :=: 1 Al2(SO4)3Molarity: 2:3:115 Al :=: 22.5 mole H2SO4 :=: 7.5 moles Al-sulfate
To find the volume of 54 grams of aluminum with a density of 2.7 g/cm3, divide the mass by the density: 54 grams / 2.7 g/cm3 = 20 cm3. Therefore, the volume of 54 grams of aluminum is 20 cubic centimeters.
By definition: Density is equal to the mass divided by the volume. You have a volume of 20 ml and a mass of 54 g.
To calculate the density of an object, divide the mass (54) by the volume (300). The answer is about 5.
The volume of water can be calculated using its density, which is approximately 1000 kg/m³. By dividing the mass of water (0.054 kg) by its density, we can find the volume. Therefore, the volume of 0.054 kg of water is approximately 0.000054 m³ or 54 cm³.
The **density** of a substance is defined as its mass per unit volume. We can calculate the density using the formula: [ \text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)} ] Given that the sample has a volume of **50 cm³** and a mass of **135 g**, let's determine the density: [ \rho = \frac{135 , \text{g}}{50 , \text{cm³}} ] The calculated density is approximately **2.7 g/cm³**[^10^]. Now let's compare this value to known densities: **Gold**: Gold has a density of *19.3 g/cm³*⁷. The sample's density is significantly lower. **Pure Water**: The density of pure water is approximately **1 g/cm³** at 4.0°C (39.2°F) . The sample's density is higher than water. **Aluminum**: Aluminum has a density of *2.7 g/cm³*[^10^]. The sample's density matches that of aluminum. **Ocean Water**: Ocean water contains dissolved salts, which increase its density. Seawater density typically ranges from *1.02 g/cm³ to 1.03 g/cm³*. The sample's density is higher than seawater. Based on the calculated density, the sample is most likely **aluminum**.
The substance has a density of about 1.704 g/mL
This is simple math. Density=Mass(grams)/Volume(milliliters) so since 3^3=27 then it works out to a simple D=54/27 aka 2. 2kg/L to be exact.
To convert liters (l) to tons, you need to know the density of the substance in question. The conversion will depend on the specific substance's density. The formula for converting volume to mass is: mass = volume x density.
Density is not mass per area, so this is invalid.
A cube, with 3cm sides, has a volume of 3x3x3 = 27cc The weight is 27grammes. Density = weight / volume = 27g / 27cc = 1g/cc = 1000Kg/M3 A relative density of 1.0 (same as water)
The density of aluminum is 2.7 gm/cc3 . So your 'cc' of aluminum contains 2.7 grams of mass. Assuming that it's located on or near the surface of the earth, it weights 0.026 newtons (0.952 ounce). (both rounded)
54 or 52