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The solubility of KCl in water at 80°C is approximately 380 g/L. To form a saturated solution, you would need to dissolve 380 g of KCl in 1 L (1000 g) of water. Since you are using 200 g of water, you would need 76 g of KCl to form a saturated solution.
Molar mass of KCl = 74.55g/mol.ie, if you dissolve 74.55g KCl in 1litre (1000 ml) of water, it will be 1M KCl solution.If you want to make 3M KCl solution,Dissolve 3 ×74.55 = 223.65g KCl in 1litre (1000 ml) of water.If you want to make different molar solutions of KCl, just calculate as per below given equation.Weight of KCl to be weighed =Molarity of the solution needed × Molecular weight of KCl (ie, 74.55) × Volume of solution needed in ml / 1000.To prepare 3M KCl in 1 litre, it can be calculated as follows,3 mol × 74.55 g/mol × 1000 ml / 1000 ml = 223.65gByPraveen P Thalichalam, Kasaragod (Dist), Kerala.
No there is no pH change KCl+H20--> K2O + HCl neither OH- or H+ is formed, which would make it either more acidic or more basic. KCl is a salt
Potassium chloride does form an aqueous solution when dissolved in water.
If a potassium chlorate sample is contaminated with KCl, the experimental percent oxygen would be lower than the theoretical percent oxygen. This is because KCl does not contain oxygen, so the contamination would dilute the amount of oxygen produced during the decomposition of potassium chlorate.
To prepare a 500mM KCl solution, you would need to dissolve 74.55 grams of KCl in enough solvent to make 1 liter of solution.
To find the number of grams in 3.75 moles of KCl, you would first calculate the molar mass of KCl, which is approximately 74.55 g/mol. Then, you would multiply this molar mass by the number of moles (3.75 moles) to get the answer, which is 279.56 grams of KCl.
The solubility of KCl in water at 80°C is approximately 380 g/L. To form a saturated solution, you would need to dissolve 380 g of KCl in 1 L (1000 g) of water. Since you are using 200 g of water, you would need 76 g of KCl to form a saturated solution.
Molar mass of KCl = 74.55g/mol.ie, if you dissolve 74.55g KCl in 1litre (1000 ml) of water, it will be 1M KCl solution.If you want to make 3M KCl solution,Dissolve 3 ×74.55 = 223.65g KCl in 1litre (1000 ml) of water.If you want to make different molar solutions of KCl, just calculate as per below given equation.Weight of KCl to be weighed =Molarity of the solution needed × Molecular weight of KCl (ie, 74.55) × Volume of solution needed in ml / 1000.To prepare 3M KCl in 1 litre, it can be calculated as follows,3 mol × 74.55 g/mol × 1000 ml / 1000 ml = 223.65gByPraveen P Thalichalam, Kasaragod (Dist), Kerala.
To make a 3 M solution of KCl, you would need to dissolve 149.5 grams of KCl (potassium chloride) in enough water to make 1 liter of solution. Weigh out the desired amount of KCl, add it to a suitable container, and then add water while stirring until the KCl is completely dissolved.
Potassium Chloride
No there is no pH change KCl+H20--> K2O + HCl neither OH- or H+ is formed, which would make it either more acidic or more basic. KCl is a salt
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
Potassium chloride does form an aqueous solution when dissolved in water.
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
To make a 1.0 M solution of KCl in 500 ml, you would need to weigh out 74.55 g of KCl (molar mass of KCl is 74.55 g/mol) and dissolve it in enough water to make a final volume of 500 ml. Remember to use a volumetric flask to accurately measure the final volume.
If a potassium chlorate sample is contaminated with KCl, the experimental percent oxygen would be lower than the theoretical percent oxygen. This is because KCl does not contain oxygen, so the contamination would dilute the amount of oxygen produced during the decomposition of potassium chlorate.