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The formula given is already the empirical formula, because its two subscripts, 5 and 14, do not have any common whole number factors except 1.

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{Another contributor wrote: "That's true, but hexane is C6H14 - and there are still no common whole number factors." This comment is wrong, because 2 is a common factor of 6 and 14.}

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The _chemical formula_ for hexane is C6H14. (This formula indicates the number of atoms of each element in one molecule of any of the _isomers_ of hexane.) The ratio of carbon atoms to hydrogen atoms in one molecule of hexane is 1:2. Therefore, the _empirical formula_ for hexane is CH2.

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What is the molecular formula of a compound if the weight is of a unit of the compound is 120 and the empirical formula is C3H4?

To find the molecular formula, you first need to calculate the empirical formula mass of C3H4. C3H4 has an empirical formula weight of 40 g/mol. If the molecular weight is 120 g/mol, then the molecular formula would be 3 times the empirical formula, so the molecular formula would be C9H12.


What is the empirical formula C12H6O3?

The principle for this kind of problem is to find the highest integer that is an integral factor of all the subscripts, then divide the subscripts by that integer. In this instance, 3 is the highest integer, since 15/3 = 5, a prime number, and 5 is not an integral factor of 9 or 3. Therefore, the empirical formula would be C3H5O.


What is the empirical formula of a compound with the molecular formula C6H12O6?

The empirical formula of a compound gives the simplest whole-number ratio of atoms present. For C6H12O6, the empirical formula would be CH2O, obtained by dividing all subscripts by the greatest common factor of 6.


The empirical formula is CH2O. What is the molecular formula of this compound?

The molecular formula of a compound is a multiple of its empirical formula, so the molecular formula is a multiple (in this case, 6 times) of CH2O, giving C6H12O6. This molecular formula corresponds to glucose, a common sugar.


What is the empirical formula of an oxide of Bromine which contains 71.4 percent Bromine by mass?

The empirical formula of the oxide of Bromine would be Br2O5. We can determine this by assuming a 100 g sample, which would contain 71.4 g of Bromine and 28.6 g of Oxygen. Then we convert these masses into moles and divide by the smaller value to find the mole ratio, which gives the empirical formula.

Related Questions

What is the empirical formula of azulene?

It has a molecular formula of C10H8 so that would make an empirical formula of C5H4.


What is an empirical formula c4h8 c2h4 ch c2h2?

CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)


How are the empirical and molecular for a compound related?

A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.


How are empirical and molecular for a compound related?

A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.


How are empirical and molecular formulas for a compound relation?

A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.


How are the Empirical and molecular formulas for compounds related?

A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.


How are the empirical molecular formulas for a compound related?

A molecular formula is identical to the empirical formula, and is based on quantity of atoms of each type in the compound.The relationship between empirical and molecular formula is that the empirical formula is the simplest formula, and the molecular can be the same as the empirical, or some multiple of it. An example might be an empirical formula of C3H8. Its molecular formula may be C3H8 , C6H16, C9H24, etc. Looking at it the other way, if the molecular formula is C6H12O6, the empirical formula would be CH2O.


How to calculate empirial formula from molecular formula?

To calculate the empirical formula from a molecular formula, divide the subscripts in the molecular formula by the greatest common factor to get the simplest ratio of atoms. This simplest ratio represents the empirical formula.


What is the molecular formula of a compound if the weight is of a unit of the compound is 120 and the empirical formula is C3H4?

To find the molecular formula, you first need to calculate the empirical formula mass of C3H4. C3H4 has an empirical formula weight of 40 g/mol. If the molecular weight is 120 g/mol, then the molecular formula would be 3 times the empirical formula, so the molecular formula would be C9H12.


What would be the empirical formula for glucose C6H12O6?

The empirical formula of glucose is the formula which has the lowest ratio. You can divide all three elements by 6 to give: CH2O.


Can an empirical formula be triple its molecular formula?

No, an empirical formula represents the simplest whole-number ratio of atoms in a compound, while a molecular formula shows the actual number of each type of atom in a molecule. Therefore, an empirical formula cannot be triple its molecular formula.


What would be the empirical formula for octane C12H16O12?

C3h4o3