The conversion factor you need for this problem is Avogadro's number.
(6.02 x 1023 atoms iron/1 mole iron) = 1
... OR ...
(1 mole iron/6.02 x 1023 atoms iron) = 1
Since you want to end up in units of atoms of Fe, this goes in the numerator (on top). You want to convert from moles Fe, so this goes in the denominator (on the bottom).
moles Fe6.02E+23 atoms Fe = atoms Fe1 mole Fe
The conversion factor you need for this problem is Avogadro's number.
(6.02 x 1023 atoms selenium/1 mole selenium) = 1
... OR ...
(1 mole selenium/6.02 x 1023 atoms selenium) = 1
Since you want to end up in units of atoms of Se, this goes in the numerator (on top). You want to convert from moles Se, so this goes in the denominator (on the bottom).
moles Se6.02E+23 atoms Se = atoms Se1 mole Se
You have to multiply the number of moles by Avogadro's number (6.022x10^23). The product of the two numbers will give you the number of atoms.
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.8.00 moles × (6.02 × 1023 atoms) = 4.82 × 1024atoms
There is no direct relationship between grams of oxygenand atoms of oxygen. Use the atomic mass to convert grams to moles and Avogadro's number to convert moles to atoms.Since you are converting from grams O, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of atoms of O, so this goes in the numerator (on the top) of the last factor.g O1.00 mole O6.02E+23 atom O= atoms O16.0 gram O1.00 mole ONote that the units grams oxygen "cancel out" in the first factor and you are left in units of moles. Moles cancel out in the second factor and the final units are atoms oxygen.
6.55 * 1024 atoms = ? moles of carbonTake the number of atoms and divide it by Avogrodos constant (6.02 * 1023). Note that if you are looking to have your units cancel, multiply the number of atoms times 1 mole and divided by atomic mass. But if you know why it is just multiplied by one, there is no reason to put it in the formula.6.55 * 1024 atoms / (6.02 * 1023) = 10.9 molescarbon
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
For this you need the atomic mass of S. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.4 mole S × (32.1 grams) = 77.0 grams S
For this you do not have to have an Atomic Mass. Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for units to cancel.2.5 moles × (6.02 × 1023 atoms) = 1.51 × 1024atoms in 2.5 moles
For this problem you don't need the atomic mass of the element. If you want to convert moles to atoms, you need to take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for units to cancel.9.00 moles C × (6.02 × 1023 atoms) = 5.42 × 1024 atoms C
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.8.00 moles × (6.02 × 1023 atoms) = 4.82 × 1024atoms
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
There is no direct relationship between grams of oxygenand atoms of oxygen. Use the atomic mass to convert grams to moles and Avogadro's number to convert moles to atoms.Since you are converting from grams O, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of atoms of O, so this goes in the numerator (on the top) of the last factor.g O1.00 mole O6.02E+23 atom O= atoms O16.0 gram O1.00 mole ONote that the units grams oxygen "cancel out" in the first factor and you are left in units of moles. Moles cancel out in the second factor and the final units are atoms oxygen.
There is no direct relationship between atoms of germanium and grams of germanium. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms Ge, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of Ge, so this goes in the numerator (on the top) of the last factor.atoms Ge1.00 mole Ge72.6 gram= g Ge6.02E+23 atom Ge1.00 mole GeNote that the units atoms germanium "cancel out" in the first factor and you are left in units of moles. Moles cancel out in the second factor and the final units are grams germanium.
The conversion factor you need for this problem is Avogadro's number.(6.02 x 1023 atoms germanium/1 mole germanium) = 1... OR ...(1 mole germanium/6.02 x 1023 atoms germanium) = 1Since you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from atoms Ge, so this goes in the denominator (on the bottom).atoms Ge1 mole Ge = moles Ge6.02E+23 atoms Ge
For this you don't need to have the atomic mass. Take the number of atoms and divide it by Avogadro's constant, 6.02 × 1023. Multiply by one mole for units to cancel.20.00 atoms Au / (6.02 × 1023 atoms) = 3.32 × 10-23 moles of Au
One mole of formula units = 6.022 x 1023 formula units.
1.203mol
For this you need the atomic (molecular) mass of H2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.3.00 moles H2 × 2.02 = 6.06 grams H2
Avogadro's constant is 6.02*10^23. This number represents the number of representative particles (atoms, molecules, or formula units) in one mole. To solve your question, we simply multiply Avogadro's constant by the number of moles. 6.02*10^23 * 2.3 = 1.38*10^24