The conversion factor you need for this problem is Avogadro's number.
(6.02 x 1023 atoms iron/1 mole iron) = 1
... OR ...
(1 mole iron/6.02 x 1023 atoms iron) = 1
Since you want to end up in units of atoms of Fe, this goes in the numerator (on top). You want to convert from moles Fe, so this goes in the denominator (on the bottom).
moles Fe6.02E+23 atoms Fe = atoms Fe1 mole Fe
There is no direct relationship between grams of oxygenand atoms of oxygen. Use the atomic mass to convert grams to moles and Avogadro's number to convert moles to atoms.Since you are converting from grams O, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of atoms of O, so this goes in the numerator (on the top) of the last factor.g O1.00 mole O6.02E+23 atom O= atoms O16.0 gram O1.00 mole ONote that the units grams oxygen "cancel out" in the first factor and you are left in units of moles. Moles cancel out in the second factor and the final units are atoms oxygen.
6.55 * 1024 atoms = ? moles of carbonTake the number of atoms and divide it by Avogrodos constant (6.02 * 1023). Note that if you are looking to have your units cancel, multiply the number of atoms times 1 mole and divided by atomic mass. But if you know why it is just multiplied by one, there is no reason to put it in the formula.6.55 * 1024 atoms / (6.02 * 1023) = 10.9 molescarbon
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
One mole of NH4 (ammonium) has one mole of nitrogen atoms and four moles of hydrogen atoms, for a total of five moles of atoms. Multiply by Avogadro's Number to convert moles of atoms to atoms.
For this you need the atomic mass of S. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.4 mole S × (32.1 grams) = 77.0 grams S
For this you do not have to have an Atomic Mass. Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for units to cancel.2.5 moles × (6.02 × 1023 atoms) = 1.51 × 1024atoms in 2.5 moles
There is no direct relationship between grams of oxygenand atoms of oxygen. Use the atomic mass to convert grams to moles and Avogadro's number to convert moles to atoms.Since you are converting from grams O, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of atoms of O, so this goes in the numerator (on the top) of the last factor.g O1.00 mole O6.02E+23 atom O= atoms O16.0 gram O1.00 mole ONote that the units grams oxygen "cancel out" in the first factor and you are left in units of moles. Moles cancel out in the second factor and the final units are atoms oxygen.
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
For this problem you don't need the atomic mass of the element. If you want to convert moles to atoms, you need to take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for units to cancel.9.00 moles C × (6.02 × 1023 atoms) = 5.42 × 1024 atoms C
For this you don't need to have the atomic mass. Take the number of atoms and divide it by Avogadro's constant, 6.02 × 1023. Multiply by one mole for units to cancel.20.00 atoms Au / (6.02 × 1023 atoms) = 3.32 × 10-23 moles of Au
To convert atoms of germanium to grams of germanium, you would need to multiply by the molar mass of germanium. The molar mass of germanium is approximately 72.63 grams per mole. This conversion factor allows you to go from the atomic scale to the macroscopic scale of grams. Simply multiply the number of atoms of germanium by 72.63 g/mol to obtain the mass in grams.
The conversion factor you need for this problem is Avogadro's number.(6.02 x 1023 atoms germanium/1 mole germanium) = 1... OR ...(1 mole germanium/6.02 x 1023 atoms germanium) = 1Since you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from atoms Ge, so this goes in the denominator (on the bottom).atoms Ge1 mole Ge = moles Ge6.02E+23 atoms Ge
Avogadro's constant is 6.02*10^23. This number represents the number of representative particles (atoms, molecules, or formula units) in one mole. To solve your question, we simply multiply Avogadro's constant by the number of moles. 6.02*10^23 * 2.3 = 1.38*10^24
1.203mol
For this you need the atomic (molecular) mass of H2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.3.00 moles H2 × 2.02 = 6.06 grams H2
One mole of formula units = 6.022 x 1023 formula units.
FORMULA UNITS TO MOLES (formula units --> moles)Divide the number of formula units by Avogadro's number.----------- Formula UnitsAvogadro's number (formula units)Conversion FactorFormula Units x 1 mol-------- Avogadro's number (formula units)MOLES TO FORMULA UNITS (moles --> formula units)Multiply the number of moles by Avogadro's number.Moles Substance x Avogadro's numberConversion FactorMol substance x Avogadro's number---------------------- 1 mol substanceMOLES TO GRAMS (moles --> grams)*Multiply the number of moles by the substance's molar mass.Moles Substance x Molar Mass SubstanceConversion FactorMol Substance x Molar Mass Substance------------------------- 1 mol SubstanceGRAMS TO MOLES (grams --> moles)*Divide the number of grams by the substance's molar mass.---- Mass (g) SubstanceMolar Mass (g) SubstanceConversion FactorMass (g) Substance x 1 mol substance----------------------- Molar Mass Substance (g)FORMULA UNITS TO GRAMS (formula units --> moles --> grams)*Divide formula units by Avogadro's number (6.022 x 1023 formula units); multiply by molar mass.--- Formula Units --- x --- Molar MassAvogadro's numberConversion FactorFormula Units x 1 mol ----------------- x -------------- Molar mass (g)---------- Avogadro's number (formula units) ----------- 1 molGRAMS TO FORMULA UNITS (grams --> moles --> formula units)*Divide mass of substance by the molar mass of substance; multiply by Avogadro's number.---- Mass (g) substance -- x -- 6.022 x 1023 moleculesMolar mass (g) substanceConversion Factor--- Mass substance (g) x 1 mol substance ------ x ----- Avogadro's number------------------------ Molar Mass (g) substance ----------- 1 mol substanceTip: On test day, anytime you see the words ions, formula units, molecules, or atoms on a question, that problem will involve the usage of Avogadro's number.*Finding Molar Mass# Atoms Element A x Atomic Mass Element A (Periodic Table) = mass (g) El. A# Atoms Element B x Atomic Mass Element B (Periodic Table) = mass (g) El. B... etc.Add up all the mass values found above and you have molar mass.