Chloride anions form a white precipitate of silver chloride when mixed in solution with silver nitrate.
Silver chloride (AgCl) gives a white precipitate. Silver Bromide (AgBr) also gives a white precipitate, though it's a slightly more creamy white than the precipitate formed by AgCl. Silver iodide (AgI) gives a pale yellow precipitate.
The light yellow solution is likely to be sodium chromate. This solution would give a white precipitate of silver chromate when treated with acidified silver nitrate due to the formation of a sparingly soluble salt, Ag2CrO4.
Silver is disolved in the acid as Silver Nitrate. Silver + Nitric Acid -> Silver Nitrate + Hydrogen
The balanced equation is: 2Ag + 2HgNO3 -> Hg + Hg(NO3)2 + 2AgNO3. This is obtained by balancing the number of atoms on both sides of the equation.
Selenium nitrate typically gives a pink or reddish flame color when subjected to a flame test.
all the organic compounds and nitrates of metals and ammonium do not form ppts with silver nitrate.
When silver nitrate (AgNO3) is mixed with sodium chloride (NaCl), a white precipitate of silver chloride (AgCl) is formed. This reaction is a double displacement reaction where the silver cation from AgNO3 and the chloride anion from NaCl switch partners to form the insoluble AgCl precipitate.
Silver chloride (AgCl) gives a white precipitate. Silver Bromide (AgBr) also gives a white precipitate, though it's a slightly more creamy white than the precipitate formed by AgCl. Silver iodide (AgI) gives a pale yellow precipitate.
The light yellow solution is likely to be sodium chromate. This solution would give a white precipitate of silver chromate when treated with acidified silver nitrate due to the formation of a sparingly soluble salt, Ag2CrO4.
Silver is disolved in the acid as Silver Nitrate. Silver + Nitric Acid -> Silver Nitrate + Hydrogen
Chloride (Cl^−), bromide (Br^−), and iodide (I^−) ions can form white precipitates with silver nitrate (AgNO3) due to the formation of silver chloride (AgCl), silver bromide (AgBr), and silver iodide (AgI), respectively. These reactions are commonly used in qualitative analysis to identify the presence of these anions in a solution.
Chloroform is non-polar and therefore does not ionize in solution, so it does not react with silver nitrate which requires ionization to form the silver chloride precipitate. On the other hand, sodium chloride is an ionic compound, so it readily dissociates into sodium and chloride ions which react with silver nitrate to form the insoluble silver chloride precipitate.
It gives green color . Copper is more reactive than silver therefore it displaces silver from silver nitrate and forms silver + copper nitrate
One way to detect the presence of Cl- ions is by using silver nitrate solution. When added to a solution containing Cl- ions, a white precipitate of silver chloride forms. Another method is using a specific electrode called a chloride ion-selective electrode, which gives a signal proportional to the concentration of Cl- ions in the solution.
In the reaction between zinc and silver nitrate, zinc displaces silver from the nitrate compound because it is higher in the reactivity series. This displacement reaction results in the formation of zinc nitrate and elemental silver.
This is probable an error.
as silver nitrate reacts with iron(AgNO3+Fe gives FeNO3+Ag)(decomposition reaction).