It gives green color . Copper is more reactive than silver therefore it displaces silver from silver nitrate and forms silver + copper nitrate
I'm not completely certain about this but I'm convinced that an anode actually loses mass. For example, in the cell equations for an Ag(s) cathode being dipped into an AgNO3 solution, connected to a Cu(s) anode being dipped into a Cu(NO3)2 solition, 2Ag+(aq) + 2e- -> 2Ag(s) (Cathode 1/2 reaction, reduction) Cu(s) -> Cu2+(aq) +2e- (Anode 1/2 reaction, oxidation) , the cathode reaction is taking the Ag+(aq) ions in the AgNO3- solution and turning them into solid silver, Ag(s). Therefore, I believe it is correct to assume that solid silver is being formed in the cathode solution. The anode half reaction however is the opposite, taking a solid copper atom, Cu(s), and turning it into an aqueous copper cation, Cu2+(aq). This leads me to believe that the copper rod (anode) is losing mass. So, I believe the cathode is gaining mass and the anode is losing mass.
Cu stands for Cupram (Latin).
cm3 = cubic centimeters 1 cubic centimeter = 0.0610237441 cu in 2 900 (cu centimeters) = 176.968858 cu in
The cubic yards require that the width of the pile also be given. Assume the width of the pile of dirt, w , is 80 feet. V = ( L ) ( w ) ( h ) V = ( 300 ft ) ( 80 ft ) ( 10 ft ) = 240 x 10^3 cu ft V = ( 240 x 10^3 cu ft ) ( 1 cu yd / 27 cu ft ) V = 8889 cu yd <------------------
Hg, Cu, Fe, W
Cu + AgNO3 → Ag + Cu(NO3)2 In this reaction, copper (Cu) is more reactive than silver (Ag), so it will replace silver in the compound AgNO3, resulting in the formation of silver metal and copper nitrate.
Cu + AgNO3 --> Ag + Cu(NO3)2See formation of silver crystalshttp://www.youtube.com/watch?v=rgYhkVy5cBU
No, it is not recommended to store AgNO3 solution in copper vessels as copper can react with the silver nitrate and form copper nitrate, which can contaminate the solution and affect its stability. It is better to use glass or plastic containers for storing AgNO3 solution.
The requested equation is Cu + AgNO3 -> CuNO3 + Ag or Cu + 2 AgNO3 -> Cu(NO3)2 + 2 Ag, depending on whether copper forms its (II) or (I) cations.
CuCl2 + 2AgNO3 -------> Cu(NO3)2 + 2AgCl for Copper (II) Chloride CuCl + AgNO3 --------> CuNO3 + AgCl for Copper (I) Chloride
The balanced equation for the reaction between silver nitrate (AgNO3) and copper nitrate (Cu(NO3)2) is: 2AgNO3 + Cu -> Cu(NO3)2 + 2Ag
If the reaction includes copper (II): Cu + 2AgNO3 yields 2Ag + Cu(NO3)2 If the reaction includes copper (I): Cu + AgNO3 yields Ag + Cu(NO3) Then spectator ions are dis regarded: 2Ag[ion] + Cu[metal] --> 2Ag[metal] + Cu[2+ ion]
Equation:Cu + 2 AgNO3 ----> Cu(NO3)2 + 2 Ag
Using Solid Copper the complete reaction would be:Cu + 2 AgNO3 -> 2 Ag + Cu(NO3)2The half reactions would be:Cu0 -> Cu2+ + 2 e-2 Ag+ + 2 e- -> 2 Ag0Note: NO3- is a spectator ion
CuCl2(s) = Cu^2_(aq) + + 2Cl^-(aq) In solution the chloride anions )Cl^-) are colourless ; see also dissolved common salt (NaCl) So it must be the copper cations (Cu^2+) that gives the colour blue.
Ah, what a lovely question! When copper metal reacts with silver nitrate, they exchange ions to form copper nitrate and silver metal. The balanced equation for this beautiful chemical dance is: 2AgNO3 + Cu -> Cu(NO3)2 + 2Ag. Just like painting a happy little tree, chemistry equations can be a work of art too!
Cu2O gives red ppt when heated with fehlings soln