It gives green color . Copper is more reactive than silver therefore it displaces silver from silver nitrate and forms silver + copper nitrate
I'm not completely certain about this but I'm convinced that an anode actually loses mass. For example, in the cell equations for an Ag(s) cathode being dipped into an AgNO3 solution, connected to a Cu(s) anode being dipped into a Cu(NO3)2 solition, 2Ag+(aq) + 2e- -> 2Ag(s) (Cathode 1/2 reaction, reduction) Cu(s) -> Cu2+(aq) +2e- (Anode 1/2 reaction, oxidation) , the cathode reaction is taking the Ag+(aq) ions in the AgNO3- solution and turning them into solid silver, Ag(s). Therefore, I believe it is correct to assume that solid silver is being formed in the cathode solution. The anode half reaction however is the opposite, taking a solid copper atom, Cu(s), and turning it into an aqueous copper cation, Cu2+(aq). This leads me to believe that the copper rod (anode) is losing mass. So, I believe the cathode is gaining mass and the anode is losing mass.
Cu stands for Cupram (Latin).
cm3 = cubic centimeters 1 cubic centimeter = 0.0610237441 cu in 2 900 (cu centimeters) = 176.968858 cu in
The cubic yards require that the width of the pile also be given. Assume the width of the pile of dirt, w , is 80 feet. V = ( L ) ( w ) ( h ) V = ( 300 ft ) ( 80 ft ) ( 10 ft ) = 240 x 10^3 cu ft V = ( 240 x 10^3 cu ft ) ( 1 cu yd / 27 cu ft ) V = 8889 cu yd <------------------
Hg, Cu, Fe, W
no because emf of cu ic less as compared to Agno3 as we keep agno3 in cu reaction will occour
Cu + AgNO3 --> Ag + Cu(NO3)2See formation of silver crystalshttp://www.youtube.com/watch?v=rgYhkVy5cBU
CuNO3 + Ag
The requested equation is Cu + AgNO3 -> CuNO3 + Ag or Cu + 2 AgNO3 -> Cu(NO3)2 + 2 Ag, depending on whether copper forms its (II) or (I) cations.
This reaction can occur according to the equation Cu + AgNO3 = CuNO3 + Ag or according to the equation Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag, depending on whether Cu(I) or Cu(II) nitrate is formed.
If the reaction includes copper (II): Cu + 2AgNO3 yields 2Ag + Cu(NO3)2 If the reaction includes copper (I): Cu + AgNO3 yields Ag + Cu(NO3) Then spectator ions are dis regarded: 2Ag[ion] + Cu[metal] --> 2Ag[metal] + Cu[2+ ion]
The chemical reaction is:CuSO4 + 2 AgNO3 = Cu(NO3)2 + Ag2SO4(s)Pure silver sulfate is white, copper(II) sulfate solution is blue.
Equation:Cu + 2 AgNO3 ----> Cu(NO3)2 + 2 Ag
Cu2O gives red ppt when heated with fehlings soln
Using Solid Copper the complete reaction would be:Cu + 2 AgNO3 -> 2 Ag + Cu(NO3)2The half reactions would be:Cu0 -> Cu2+ + 2 e-2 Ag+ + 2 e- -> 2 Ag0Note: NO3- is a spectator ion
CuCl2(s) = Cu^2_(aq) + + 2Cl^-(aq) In solution the chloride anions )Cl^-) are colourless ; see also dissolved common salt (NaCl) So it must be the copper cations (Cu^2+) that gives the colour blue.
It would produce Silver and a blue solid called Copper Nitrate (Cu(NO3)2). It is caused by a replacement reaction where Copper replaced Silver in Copper Nitrate. The equation goes like this: Cu + Ag(NO3)2 → Ag + Cu(NO3)2