Ag and Al
MgCl2 because it has more electrons (due to the Mg over Na). Because of the higher number of electrons, it has higher dispersion forces (attractive forces). This means that more energy (heat) is required to unstick the molecules into a different state of matter.NaCl, due to complex arrangement and interaction of molecules, can't be easily explained by using simple dispersion, dipole-dipole interaction.Although NaCl's higher melting point can be explained by its bonding in its crystal lattice arrangement compare to MgCl2.
No, a binary ionic compound is composed of two elements in which one is a negatively charged ion, and the other a positively charged ion. Examples include the following: NaCl, LiF, MgO, MgCl2, K2O
Some familiar compound elements include water (H2O), carbon dioxide (CO2), and sodium chloride (NaCl). These compounds consist of two or more different elements bonded together chemically.
combusion, solium and chloride For example sodium chloride may be obtained by the following reaction: NaOH + HCl = NaCl + H2O
Solid NaCl is not an electrical conductor as the ions are held in a fixed lattice structure. Molten NaCl and aqueous solution NaCl are electrical conductors as the ions are free to move and carry charge, allowing for the conduction of electricity.
add Nacl and mgcl2
Depends on the compound; chlorine can form an ionic bond with many elements. eg, NaCl, MgCl2, CsCl.
Formulas (not equations) are: MgCl2, NaCl.
No, there will be more molecules in the 50 grams of NaCl, because its molacular weight is lower. NaCl has a molaculair mass of 58.44 g/mol and MgCl2 has a molcular mass of 95.21 g/mol. 50 g / 58.44 g/mol = 0.86 mol NaCl 50 g / 95.21 g/mol = 0.53 mol MgCl2 The avogadro contstant states that 1 mole equals 6.02214179*1023 molecules. So you have 0.86 * 6.022*1023 = 5.18*1023 molecules of NaCl and 0.53 * 6.022*1023 = 3.19*1023 molecules of MgCl2.
In the same volume of water, one mole of MgCl2 will give rise to a greater boiling point elevation. This is explained by the fact that boiling point elevation is a colligative property, that is, the relative amounts of the constituents are important and not their identity. We can determine by inspection that, upon dissociation, more ions will be produced by MgCl2 than NaCl since there are more atoms in the MgCl2 molecule. So, for one mole of MgCl2, we will produce one mole of magnesium and two of chlorine (three total). For one mole of NaCl, we produce one mole each of potassium and chlorine. By employing the principle stated above, we can come to the correct conclusion.
Na + MgCl2 ----> NaCl + Mg is the chemical equation so yes
The mole ratio for the given equation is 1:2:1:1. This means for every 1 mole of MgSO4, we need 2 moles of NaCl to react and produce 1 mole of Na2SO4 and 1 mole of MgCl2.
The magnesium chloride solution has a higher boiling point.
MgCl2 because it has more electrons (due to the Mg over Na). Because of the higher number of electrons, it has higher dispersion forces (attractive forces). This means that more energy (heat) is required to unstick the molecules into a different state of matter.NaCl, due to complex arrangement and interaction of molecules, can't be easily explained by using simple dispersion, dipole-dipole interaction.Although NaCl's higher melting point can be explained by its bonding in its crystal lattice arrangement compare to MgCl2.
No, a binary ionic compound is composed of two elements in which one is a negatively charged ion, and the other a positively charged ion. Examples include the following: NaCl, LiF, MgO, MgCl2, K2O
NO!!! In one molecule of NaCl there are TWO(2) ions ; Na^(+) & Cl^(-) In one molecule of MgCl2 there are THREE(3) ions ; Mg^(2+) , Cl^(-) & Cl^(-) . Hence it follows that in one mole of NaCl there are less ions than there are in one mole of MgCl2, by a ratio of 2:3 .
Your question appears to lack some necessary detail. Sodium is Na Magnesium Chloride is MgCl2 "What is the equation for sodium and magnesium chloride?" = Na + MgCl2 Is that what you are asking or do mean what is the equation for sodium ___x___ and magnesium chloride? Magnesium chloride appears commercially as a solution in water from 0-35% MgCl2, or an anhydrous solid 98% MgCl2 or hexahydrate solid 47% MgCl2. What is the form of sodium you are trying to use? NaOH? NaCl? ??