because the substance in the potassium permanganate crystals are permeable to water, so that means it will dissolve instantly while poured into water
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4 Cis- and trans potassium dioxalatodiaquachromato (III) Materials required:Oxalic acid, potassium dichromate a)Trans isomer of K{Cr(C2O4)2(H2O)2|3H2O Dissolve 12 g of oxalic acid monohydrate in a minimum amount of boiling water in a 250 ml beaker. Add in small portions a solution of 4 g of potassium oxalate in a minimum of hot water, covering the beaker while the violent reaction proceeds. Evaporate the solution to about one third of its original volume. Filter the crystals and wash with cold water and ethanol. A high yield cannot be expected since only a part of the product is isolated. Note that in solution there is an equilibrium between the cis- and thetrans isomer, but the low solubility of the trans isomer results in its initial deposition. Excessive spontaneous evaporation should be avoided since otherwise the product may be contaminated with the cis isomer. b) Cis isomer of K{CR(C2O4))(H2O)2}2H2O Prepare an intimate mixture of finely ground potassium dichromate(4 g) and oxalic acid dihydrate (12 g) and heap the powder in a 15 cm diameter evaporating dish. Place one drop of water in a small depression in the mixture and cover the dish with a watch glass. After a short induction period the reaction commences and soon becomes vigorous with the evolution of steam and carbon dioxide. A solution of the product cannot be formed, and hence an equilibrium mixture of cis- and trans-isomers is not formed. The outcome of this reaction is a purple viscous liquid to which is added 20 ml of ethanol. The mixture is stirred until the reaction product solidifies. If solidification is slow, decant the liquid and repeat with a second portion of ethanol until the product is entirely crystalline. Filter at the pump. ** Purity test of the isomers:Place a few crystals of the complex on a filter paper and add a few drops of diluted aqueous ammonia. The cis-isomer rapidly forms a deep green solution which spreads over the filter paper, and no solid remains. The trans-isomer forms a light brown solid which remains undissolved. These changes are due to the formation of cis- and trans- dioxalatohydroxoaquachromium(III) ions.
It increases the effective surface area of the compound that is exposed to the acid molecules. It also allows a solution to be stirred to further increase the rate of interaction between acid and base molecules.
Homogeneous. because a solution is the same all the way throughout. Like stirred lemonade. The same way, homo in homogeneous means same.
the use of a stirred oil bath, an electrical heating element, a thermometer and a capillary tube along with a magnifying glass is usually used for determining the melting point of crystalline solids. All of these may be found handily contained in a Hoover apparatus.
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As you are not agitating and breaking away the sugar crystals, the outer layers have to dissolve before the inner layers can, causing the sugar to take longer to dissolve.
Yes
yes
saturated
Yes, stirring help the dissolution.
No, not at all
around 6-7 mins
A saturated solution will usually dissolve more solid solutes if it is stirred or heated.
if the water is hot,the solvent will dissolve faster and when it gets stirred it will dissolve even faster than when it wasn't. but if the water is cold it will dissolve slower than hot water even when stirred.
The sugar crystals have no added colour and are 'white' crystals in appearance. Once dissolved into the water, they create a transparent sugary solution. The same is for salt crystals that create a saline solution.
Stirring prevents super cooling by inducing nucleation