The conc of positive to negative ions will play some part. however, the main thing i'd imagine is the bulkiness of Al and Ca vs Na
the ion ratios are different,
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
CaCl2 → Ca2+ and 2Cl-
Only chemical formulas, not if they are reacting. Na2CO3 and CaCl2
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
the ion ratios are different,
Ionic compounds are salts or oxides as NaCl, LiF, MgCl2, MgO, UCl4, ThO2, CsCl, CaCl2, FeCl3, AlCl3.
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)
Only chemical formulas, not if they are reacting. Na2CO3 and CaCl2
The name of CaCl2 is Calcium Chloride
CaCl2 → Ca2+ and 2Cl-
Yes, CaCl2 will dissolve in water.
CaCl2 is Calcium Chloride.
It depends on what it's reacting with. If it's not reacting with anything, then CaCl2 makes...CaCl2.
The one that has the most particles or the most ions. For example, AlCl3 (4 ions) lowers freezing point more than CaCl2 (3 ions), which is better than NaCl (2 ions) which is better than glucose (1 particle).
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.