Atoms always want to have 8 electrons in their outer shell. Calcium only has two so its easier for it to give those away than to aquire 6 more. When these electrons are gone, that "shell" no longer exists so its got 8.
Calcium would need to lose 2 electrons to have 8 valence electrons. This is because calcium has 2 valence electrons in its outer shell, and by losing these 2 electrons, it can achieve a stable octet configuration like the noble gas argon.
A calcium atom typically loses two electrons to form a calcium ion with a 2+ charge. The loss of these electrons allows the calcium ion to achieve a stable electron configuration similar to that of a noble gas.
I believe it is 2, seeing it is a metal, and has 2 valence electrons. Correct me if I'm wrong, I don't have my periodic table with me (Calcium -> Ca?).
To become more stable, calcium is likely to lose two electrons to achieve a full outer shell of electrons, forming a positive 2+ ion.
The ionic charge is +2: The atom has equal numbers of positively charged protons and negatively charged electrons. The number of protons is the same in the atom and the ion, but in the ion two negative charges have been lost, so that the ion has a net charge of +2.
Having just 18 electrons make Calcium nobel.
The calcium atom (Ca) loses two valence electrons to form a calcium ion (Ca2+).
A calcium atom must lose 2 electrons to have 8 valence electrons, achieving a full outer shell and stability. Calcium is in group 2 of the periodic table, so it has 2 valence electrons originally. By losing 2 electrons, it will have a stable electron configuration similar to a noble gas.
The valence electrons of calcium will tend to give away electrons, as it is an alkaline earth metal with two valence electrons. This makes it more energetically favorable for calcium to lose these two electrons and achieve a full outer electron shell by forming a 2+ cation.
Electrons in the outer most shell are called Valence Electrons.
Calcium will lose 2 electrons when forming a Ca2+ ion. This is because calcium has 2 electrons in its outer shell, and it is energetically favorable for it to lose these electrons to achieve a stable octet configuration.
The neutral atom of calcium has 20 electrons; the cation Ca2+ has 18 electrons.
A calcium atom will normally lose its two valence electrons, which have principal quantum number 4, to a more electronegative atom when forming a compound. When this happens, the already filled electron shell with principal quantum number 3 becomes the outer shell of the resulting calcium cation, and this cation has the electronic structure of the noble gas preceding calcium in the periodic table, neon
If an atom has three electrons, it will have one valence electron (valance = outer shell). It will be more likely to lose an electron than gain one, since it has only one to lose, but seven to gain.
Calcium will lose two electrons to gain the noble gas configuration of Argon.
A calcium ion (Ca2+) loses two electrons from an atom to achieve a stable octet electron configuration. This results in a +2 charge on the calcium ion.
Calcium would need to lose 2 electrons to have 8 valence electrons. This is because calcium has 2 valence electrons in its outer shell, and by losing these 2 electrons, it can achieve a stable octet configuration like the noble gas argon.