Generally polar solute dissolve in polar solvent.KI & water both polar.when KI react with water due to hydrogen bonding & solvation(i.e.K&I ions are surrounded by water molecule) KI dissolves in water.
To prepare a 10% potassium iodide solution, dissolve 10 grams of potassium iodide in 90 ml of water. Don't forget to wear appropriate protective gear like gloves and goggles. Stir the mixture well until the potassium iodide is fully dissolved.
3% = 3 g solute / 100 g water So, for 200 g water, you will need 2X3 g = 6 grams potassium iodide This assumes that what's meant is "weight percent", sometimes abbreviated as "w/w %" or "wt %". It would be highly unusual for a chemist to specify the concentration as a percent.
To prepare iodine solution, dissolve iodine crystals in a mixture of water and potassium iodide (KI). The ratio of iodine to KI will determine the concentration of the solution. The solution should be stored in a dark bottle to prevent degradation from light exposure.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Potassium iodide is a good conductor of electricity as it dissociates into ions when dissolved in water, allowing the flow of electric current. The conductivity of potassium iodide solution depends on its concentration - higher concentrations result in higher conductivity.
Potassium iodide dissolves in water due to the ionic interaction between the potassium and iodide ions with water molecules. The polar nature of water molecules allows them to surround and separate the ions in the solid potassium iodide, causing it to break apart and dissolve in water.
Yes, both potassium and iodide are soluble in water. Potassium ions (K+) and iodide ions (I-) readily dissolve in water due to their ionic nature and ability to form strong interactions with water molecules.
To prepare a 5% potassium iodide solution, weigh 5 grams of potassium iodide and dissolve it in 100 mL of water. Stir until the potassium iodide is completely dissolved to achieve a 5% solution.
To make a 3.0% solution of potassium iodide, you would need to dissolve 6.0 g of potassium iodide in 200 g of water. This is because 3.0% of 200 g is 6.0 g.
To prepare a 10% potassium iodide solution, dissolve 10 grams of potassium iodide in 90 ml of water. Don't forget to wear appropriate protective gear like gloves and goggles. Stir the mixture well until the potassium iodide is fully dissolved.
Potassium iodide is ionic.
3% = 3 g solute / 100 g water So, for 200 g water, you will need 2X3 g = 6 grams potassium iodide This assumes that what's meant is "weight percent", sometimes abbreviated as "w/w %" or "wt %". It would be highly unusual for a chemist to specify the concentration as a percent.
Potassium iodide is a salt and will dissociate into potassium ions and iodide ions in water, so it is considered a base.
Dissolve each of the silver nitrate and potassium iodide separately in water, then mix the two solutions slowly with stirring. Silver iodide will precipitate and can be separated by filtering it from the liquid.
Potassium iodide (KI) is soluble in water, meaning it can dissolve and form a homogeneous solution when mixed with water.
No, they do not
Yes, iodide ions readily dissolve in water to form an aqueous solution. This results in the dispersion of individual iodide ions throughout the water, allowing them to interact with the water molecules.