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How would you prepare 400ml of a 0.24M NaCl solution?
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
What mass of water is needed to dissolve 292.5g of NaCl to produce 0.25 m aqueous solution?
m (molality)=moles of solute/kg of solvent To calculate moles of solute you convert 292.5 g of NaCl to moles of NaCl. So (292.5gNaCl)(1mole NaCl / 58.4gNaCl)= 5.0085 moles NaCl Now plug and chug. 0.25m=5.0085moles NaCl / x x=5.0085 moles NaCl /.25m x=20kg
How many grams of NaCl will be produced from 13g Cl2?
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
What is the molality of .630g of NaCl dissolved in 525g of water?
To find molality, first convert grams of NaCl to moles: 0.630g NaCl / 58.44 g/mol NaCl = 0.0108 mol NaCl. Next, calculate molality using moles of solute and mass of solvent: molality = moles of solute / kg of solvent = 0.0108 mol NaCl / 0.525 kg water = 0.0206 mol/kg.
What would be the molarity of a 5 percent NaCl solution?
To calculate the molarity of a 5% NaCl solution, you need to know the density of the solution. Once you have the density, you can convert the percentage to grams per liter. Then, using the molar mass of NaCl (58.44 g/mol), you can calculate the molarity using the formula Molarity = (mass of solute in g) / (molar mass of solute in g/mol) / (volume of solution in L).
The concertration of a water solution of NaCl is 2.48m and it contains 806 g of water How much NaCl is in the solution?
To determine the amount of NaCl in the solution, you first need to calculate the moles of NaCl present. Using the given molarity (2.48 M) and the volume of the solution (assumed to be 806 g = 806 ml for water), you can find the moles of NaCl. Then, you convert the moles of NaCl to grams using the molar mass of NaCl (58.44 g/mol) to find the amount of NaCl in the solution.
How do you make 1000ppm standard of Na using the salt NaCl?
To make a 1000 ppm Na standard solution using NaCl, you would dissolve 0.0585 grams of NaCl (molecular weight of NaCl = 58.44 g/mol) in 1 liter of water. This would give you a solution with a concentration of 1000 ppm Na.
How much nacl is required for a 200 mM NaCl solution?
You need 58,44 mg of ultrapure NaCl; dissolve in demineralized water, at 20 0C, in a thermostat, using a class A volumetric flask of 1 L.
What is the written out chemical formula for neutralization using NaOH and HCI?
nacl
How would you prepare 400ml of a 0.24M NaCl solution?
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
How do you write salt water using the periodic table?
Table salt is sodium chloride and it is represented as NaCl
What mass of water is needed to dissolve 292.5g of NaCl to produce 0.25 m aqueous solution?
m (molality)=moles of solute/kg of solvent To calculate moles of solute you convert 292.5 g of NaCl to moles of NaCl. So (292.5gNaCl)(1mole NaCl / 58.4gNaCl)= 5.0085 moles NaCl Now plug and chug. 0.25m=5.0085moles NaCl / x x=5.0085 moles NaCl /.25m x=20kg
How many grams of NaCl will be produced from 13g Cl2?
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
What process is used to separate Fe from NaCl?
One method to separate Fe from NaCl is by using a magnet to attract and remove the iron (Fe), as it is magnetic, while leaving the sodium chloride (NaCl) behind. This process is known as magnetic separation.
How much hcl gas can be produced at stp by reacting 131 g of nacl with excess h2so4?
Using the equation: 2 NaCl + H2SO4 -> 2 HCl + Na2SO4, we can see that 1 mole of NaCl will produce 1 mole of HCl. First, calculate the moles of NaCl (131g / 58.44g/mol). Then, using the mole ratio from the equation, you can find the moles of HCl produced. Finally, using the ideal gas law, you can convert the moles of HCl to volume at STP.
How do you find the density of NaCl?
To find the density of NaCl (sodium chloride), you first need to determine the mass of a known volume of NaCl. This can be done by weighing a sample of NaCl using a balance. Next, measure the volume of the NaCl sample using a graduated cylinder or other measuring device. Finally, divide the mass of the NaCl sample by its volume to calculate the density, which is typically expressed in grams per cubic centimeter (g/cm^3).
