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Q: Why doesn't using a colorimeter work on NaCl as it does for NiSO4?
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What is the term for the product of an acid-base reaction in addition to water?

product of acid and base neutralization would be water and salt(doesnt have to be NaCl) example HCl + NaOH -> NaCl + H2O


How much nacl is required for a 200 mM NaCl solution?

You need 58,44 mg of ultrapure NaCl; dissolve in demineralized water, at 20 0C, in a thermostat, using a class A volumetric flask of 1 L.


How do you make 1000ppm standard of Na using the salt NaCl?

Take 1000 ml volumetric flask weigh 2.542 g of Nacl


What is the written out chemical formula for neutralization using NaOH and HCI?

nacl


How do you make without using salt?

We can use potassium chloride or better a mix NaCl + KCl.


How many moles are present in 234g of NaCl?

1 mole NaCl = 58.443g NaCl 234g NaCl x 1mol NaCl/58.443g NaCl = 4.00 moles NaCl


How is the mass compound determined from the number of moles?

Multiply the number of moles times the molar mass of the compound. Moles cancel and you are left with mass in grams.For example: What is the mass of 2.47 moles of sodium chloride, NaCl?Known: The molar mass of NaCl is 58.44g/mol. (Using atomic weights in grams from the periodic table.)Solution:2.47mol NaCl x 58.44g/mol NaCl = 144g NaCl


How many grams are in 0.48 moles if NaCl?

1 mole NaCl = 58.44g NaCl0.48mol NaCl x 58.44g NaCl/1mol NaCl = 28g NaCl


How would you prepare 260 mL of 0.340M NaCl solution using an available 2.50M solution?

Dilute it.


How do you write salt water using the periodic table?

Table salt is sodium chloride and it is represented as NaCl


How mny moles are in 23.34 of NaCl?

I'm going to assume that you mean 23.34g of NaCl. 1 mole NaCl = 58.442g NaCl (the atomic weight of Na and Cl in grams) 23.34g NaCl x (1mol NaCl/58.442g NaCl) = 0.3994mol NaCl


How much grams of NaCl crystals are required to prepare 0.1N NaCl solution?

Molar mass of NaCl =~58.4 g/mole0.1 N NaCl = 0.1 moles/liter To make 1 liter of 0.1N NaCl thus requires 0.1 moles/liter = 0.1 moles x 58.4 g/mole = 5.84 moles Dissolve 5.84 g (6 g using 1 sig. fig.) in a final volume of 1 liter to make 0.1N NaCl