how do you determine degree of deacetylation of chitosan using UV -vis spectrophotometer
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
In a homogeneous mixture, KCl is dissolved uniformly in the solvent, creating a single-phase solution where the KCl particles are evenly distributed and not visible to the naked eye. In a heterogeneous mixture, KCl exists as visible particles suspended in the solvent without fully dissolving, creating a two-phase system where the KCl particles can settle out over time due to gravity.
Because Potasium dichromate (Potassium Dichromate solvated in dilute (0.001N) perchlorate acid) gives absorption at two characteristics wavelength at 235nm to 350nm ( for 20mg/L to 100mg/L) and 430nm (for 600mg/L) that's why used in wide range for linerity test of spectrophotometer.
To determine the amount of KCl decomposed, first calculate the moles of O2 produced using its molar mass. Then use the mole ratio of O2 to KCl in the reaction (3:2) to find the moles of KCl decomposed. Finally, convert the moles of KCl decomposed to grams using its molar mass to get the final answer.
To prepare a 0.01M KCl (potassium chloride) solution in 1 liter, you would need to dissolve 0.74 grams of KCl in enough water to make 1 liter of solution. This can be calculated using the formula: moles = Molarity x Volume (in liters) x Molecular weight of KCl.
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
In a homogeneous mixture, KCl is dissolved uniformly in the solvent, creating a single-phase solution where the KCl particles are evenly distributed and not visible to the naked eye. In a heterogeneous mixture, KCl exists as visible particles suspended in the solvent without fully dissolving, creating a two-phase system where the KCl particles can settle out over time due to gravity.
Because Potasium dichromate (Potassium Dichromate solvated in dilute (0.001N) perchlorate acid) gives absorption at two characteristics wavelength at 235nm to 350nm ( for 20mg/L to 100mg/L) and 430nm (for 600mg/L) that's why used in wide range for linerity test of spectrophotometer.
To calculate the amount of KCl needed, we first need to find the number of moles of KCl required using the formula: moles = Molarity x Volume (in L). Then, we convert moles to grams using the molar mass of KCl, which is 74.55 g/mol. Finally, we use the formula: grams = moles x molar mass to find that approximately 6.33 grams of KCl are needed to prepare 125 mL of a 0.720 M solution.
To determine the amount of KCl decomposed, first calculate the moles of O2 produced using its molar mass. Then use the mole ratio of O2 to KCl in the reaction (3:2) to find the moles of KCl decomposed. Finally, convert the moles of KCl decomposed to grams using its molar mass to get the final answer.
To prepare a 1.20 M potassium chloride (KCl) solution in 2.00 L of water, you would need to add 144 grams of KCl. This calculation can be determined using the formula: moles = Molarity x volume (in liters). Then, convert moles to grams using the molar mass of KCl.
To find the volume of the solution, first calculate the number of moles of KCl in 2.39g using its molar mass (74.55 g/mol). Then, use the molarity equation (Molarity = moles of solute / volume of solution in liters) to find the volume of the solution.
To prepare a 0.01M KCl (potassium chloride) solution in 1 liter, you would need to dissolve 0.74 grams of KCl in enough water to make 1 liter of solution. This can be calculated using the formula: moles = Molarity x Volume (in liters) x Molecular weight of KCl.
To find the moles of KCl in the solution, we first calculate the amount of KCl in 50.0 mL using the concentration. Volume (in liters) = 50.0 mL / 1000 = 0.050 L. Moles of KCl = Concentration x Volume = 0.552 mol/L x 0.050 L = 0.0276 moles of KCl.
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
The solubility of KCl in water at 80°C is approximately 380 g/L. To form a saturated solution, you would need to dissolve 380 g of KCl in 1 L (1000 g) of water. Since you are using 200 g of water, you would need 76 g of KCl to form a saturated solution.
KCl is soluble in water, so when added to water it will dissolve easily. PbCl2, on the other hand, is insoluble in water and will form a white precipitate. By observing whether the compound dissolves or forms a precipitate in water, you can distinguish between KCl and PbCl2.