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Why is the reaction between barium chloride and sodium sulphate also called presipitation reaction?
It is because the white precipitate of barium sulphate by the reaction of SO4(VALENCY -2) AND BA2.THE OTHER PRODUCTS FORMED IS SODIUM CHLORIDE WHICH remains in the solution. This is an example of double displacement reaction. NA2SO4(aq)+BACl2(aq) -- BASO4(S)+2NACl(aq)
Barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride?
Yes, it is true. The equation of reaction is :- BaCl2 + Na2SO4 --------> 2NaCl(aq.) + BaSO4 where solution is of sodium chloride and Barium sulphate settles down at the bottom as precipitate
When agno3 reacts with bacl2 agcl and bano32 are formed how many grams of agcl are formed when 10.0g of silver nitrate reacts with 15.0g of bacl2?
To find the amount of AgCl formed, we first need to calculate the limiting reagent. This is done by converting the given masses of AgNO3 and BaCl2 to moles, determining the mole ratio between them, and then the limiting reagent based on the smaller value. Once the limiting reagent is determined, use the mole ratio from the balanced chemical equation to find the moles of AgCl formed and then convert that to grams.
If 57.0 mL of BaCl2 solution is needed to precipitate all the sulfate ion in a 742 mg sample of Na2SO4 what is the molarity of the solution?
To find the molarity of the BaCl2 solution, first calculate the moles of Na2SO4 in the sample using its molar mass. Then, use the balanced chemical equation of the precipitation reaction to determine the moles of BaCl2 needed to react with the moles of Na2SO4. Finally, divide the moles of BaCl2 by the volume of the solution in liters (57.0 mL = 0.057 L) to find the molarity.
How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
What is the word equation for BaCl2 Na2SO4?
barium chloride plus sodium sulphate yields barium sulphate plus sodium chloride
What is the ionic equation for the reaction between barium chloride and copper sulphate?
BaCl2 + CuSO4 = BaSO4 = CuCl2
Barium chloride reacts with aluminium sulphate to give aluminium chloride and precipitate of barium sulphate?
The balanced chemical equation for this reaction is BaCl2 + Al2(SO4)3 -> 2AlCl3 + 3BaSO4. In this reaction, a double displacement reaction occurs where the cations and anions of the reactants switch partners to form the products. Barium sulphate, which is insoluble, precipitates out of the solution.
How do you make BaCl2 solution?
To make a BaCl2 (barium chloride) solution, first weigh out the appropriate amount of BaCl2 powder. Then dissolve it in a known volume of water, making sure the BaCl2 is completely dissolved. Finally, dilute the solution to reach the desired concentration, if needed.
What is the pH of BaCl2?
Barium chloride (BaCl2) is a salt compound that dissociates in solution to form Ba2+ and 2Cl- ions. Since it does not contain any acidic or basic groups that can donate or accept protons, it does not affect the pH of the solution. Therefore, the pH of a solution of BaCl2 would remain neutral around 7.
Why is the reaction between barium chloride and sodium sulphate also called presipitation reaction?
It is because the white precipitate of barium sulphate by the reaction of SO4(VALENCY -2) AND BA2.THE OTHER PRODUCTS FORMED IS SODIUM CHLORIDE WHICH remains in the solution. This is an example of double displacement reaction. NA2SO4(aq)+BACl2(aq) -- BASO4(S)+2NACl(aq)
What happens when sodium sulphate react with barium chloride?
sodium carbonate and barium chloride react to form sodium chloride and barium carbonate Na2CO3 +BaCl2 -------> 2NaCl +BaCO3
Is BaCl2 soluble or insoluble?
Yes, barium chloride (BaCl2) is soluble in water.
What is the solution for FeSo4 plus BaCL2?
The reaction between FeSO4 (iron(II) sulfate) and BaCl2 (barium chloride) will produce a precipitate of barium sulfate (BaSO4) and iron(II) chloride (FeCl2) in solution. The balanced chemical equation for the reaction is: FeSO4 + BaCl2 -> BaSO4 + FeCl2.
Barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride?
Yes, it is true. The equation of reaction is :- BaCl2 + Na2SO4 --------> 2NaCl(aq.) + BaSO4 where solution is of sodium chloride and Barium sulphate settles down at the bottom as precipitate
Why is NaOH heated before adding BaCl2?
Heating NaOH before adding BaCl2 helps to dissolve NaOH completely in water, ensuring that no solid NaOH remains undissolved in the solution. This is important because the reaction between BaCl2 and NaOH requires the NaOH to be in solution to react with the BaCl2. Heating the solution can also speed up the reaction between NaOH and BaCl2.
What is the chemical equation for the reaction between barium chloride and zinc sulphate?
In aqueous medium. ZnSO4 + BaCl2 = BaSO4 + ZnCl2.
