Yes it will. This is a Chlorine atom accepting an electron to become a chloride ion.
Barium, with an atomic number of 56, needs to lose 2 electrons to achieve a stable electron configuration, similar to a noble gas. This is because barium will then have a filled outer electron shell, following the octet rule.
Chlorine has seven valence electrons out of a possible eight, so it can easily accept another electron to achieve a full octet and become stable (like the noble gas configuration). Accepting a second electron would require more energy and result in a less stable configuration.
Bromine can both lend and accept electrons, depending on the chemical reaction it is involved in. As a halogen, bromine typically accepts an electron to complete its octet and achieve a stable electron configuration.
A negative chlorine atom readily accepts another electron because it wants to achieve a full outer electron shell, which is more stable. By gaining one more electron, chlorine can achieve a full valence shell with eight electrons, following the octet rule.
Sodium has one electron in its outer shell, so it tends to lose that electron to achieve a full outer shell. This makes sodium more stable as it follows the octet rule by having a complete outer electron shell with eight electrons.
BCL3 is a Lewis acid because it can accept an electron pair from a Lewis base. Boron in BCl3 has an incomplete octet, making it electron deficient and capable of accepting an electron pair to complete its octet, giving it a positive charge.
The electron affinity of chlorine is higher than sulfur because chlorine has a smaller atomic size and higher effective nuclear charge, resulting in stronger attraction for incoming electrons. Additionally, the electron configuration of chlorine allows for a stable octet when gaining an electron, making it energetically favorable to accept an additional electron.
-1. Fluorine has an atomic number of 9. It has seven valence electrons (in the 2d shell) so it gains one electron to achieve th octet- hence it has an oxidation number of -1
The atomic size of an element is primarily determined by the number of electron shells and the effective nuclear charge experienced by the outermost electrons. In the case of argon and chlorine, argon has an additional electron shell compared to chlorine, resulting in a larger atomic size. This additional electron shell in argon leads to greater electron-electron repulsions that push the outer electrons farther away from the nucleus, increasing the atomic size.
Barium, with an atomic number of 56, needs to lose 2 electrons to achieve a stable electron configuration, similar to a noble gas. This is because barium will then have a filled outer electron shell, following the octet rule.
The electron energy level arrangement for potassium (atomic number 19) is 2-8-8-1, following the octet rule. This means that there are 2 electrons in the first energy level, 8 electrons in the second energy level, 8 electrons in the third energy level, and 1 electron in the fourth energy level.
Chlorine has seven valence electrons out of a possible eight, so it can easily accept another electron to achieve a full octet and become stable (like the noble gas configuration). Accepting a second electron would require more energy and result in a less stable configuration.
An octet of electrons is when the outermost electron shell of an atom contains eight electrons.
Cations donate electrons from their valance shell, have less, to reach their octet state. Anions accept electrons into their valance shell, have more, to reach their octet state.
The atomic symbol for the noble gas with the same electron configuration as Cl⁻ (chloride ion) is Ar, which stands for argon. Chlorine typically has 17 electrons, and when it gains an electron to become Cl⁻, it has 18 electrons, matching the electron configuration of argon. Thus, both Cl⁻ and Ar have a complete octet, characteristic of noble gases.
Bromine can both lend and accept electrons, depending on the chemical reaction it is involved in. As a halogen, bromine typically accepts an electron to complete its octet and achieve a stable electron configuration.
A full octet makes the noble gases nonreactive.