H3O+(aq) + ClO-(aq) HClO(aq) + H2O(l)
Strong Acid + Weak Base
100% extent of reaction
2H3O+(aq) + Ca(OH)2(s) -> 4H2O(l) + Ca2+(aq)
Perchloric acid is a strong acid. Sodium hydroxide is a strong base. HClO4(aq) + NaOH(aq) ---> Na+(aq) + ClO4-(aq) + H2O(l) This is a balanced chmical reaction since the products and reacts have a 1:1 ratio.
The balanced chemical equation for the reaction between hypochlorite ion (OCl-) and thiosulfate ion (S2O3^2-) is: 2OCl- + 2S2O3^2- -> 2Cl- + S4O6^2- + 2OH-
The reaction between sodium acetate and perchloric acid would result in the formation of acetic acid and sodium perchlorate. The balanced chemical equation for the reaction is: CH3COONa + HClO4 → CH3COOH + NaClO4
The balanced chemical equation for the reaction between perchloric acid (HClO4) and sodium hydroxide (NaOH) is: HClO4 + NaOH → NaClO4 + H2O This equation shows that one molecule of HClO4 reacts with one molecule of NaOH to produce one molecule of NaClO4 and one molecule of water (H2O).
the balanced equation for ammonium hydroxide and perchloric acid is given below.NH4OH (aq) + HCl (aq) ---> NH4Cl (aq)+ H2O (l) .Above is the balanced molecular Equation.
2H3O+(aq) + Ca(OH)2(s) -> 4H2O(l) + Ca2+(aq)
Perchloric acid is a strong acid. Sodium hydroxide is a strong base. HClO4(aq) + NaOH(aq) ---> Na+(aq) + ClO4-(aq) + H2O(l) This is a balanced chmical reaction since the products and reacts have a 1:1 ratio.
This equation is NaClO (aq) + 2 HCl (aq) = NaCl (aq) + Cl2 + H2O.
The balanced chemical equation for the reaction between hypochlorite ion (OCl-) and thiosulfate ion (S2O3^2-) is: 2OCl- + 2S2O3^2- -> 2Cl- + S4O6^2- + 2OH-
The reaction between perchloric acid (HClO4) and zinc (Zn) produces zinc perchlorate [Zn(ClO4)2] and hydrogen gas (H2) as products. The balanced chemical equation for the reaction is: 2 HClO4 + Zn -> Zn(ClO4)2 + H2
The reaction between sodium acetate and perchloric acid would result in the formation of acetic acid and sodium perchlorate. The balanced chemical equation for the reaction is: CH3COONa + HClO4 → CH3COOH + NaClO4
The balanced chemical equation for the reaction between perchloric acid (HClO4) and sodium hydroxide (NaOH) is: HClO4 + NaOH → NaClO4 + H2O This equation shows that one molecule of HClO4 reacts with one molecule of NaOH to produce one molecule of NaClO4 and one molecule of water (H2O).
Na2O+H2O--->2NaOH
The net ionic equation for perchloric acid (HClO4) and sodium hydroxide (NaOH) is: H+(aq) + OH-(aq) → H2O(l). This represents the reaction between the hydronium ion and hydroxide ion to form water.
The balanced chemical equation for the reaction between perchloric acid (HClO4) and potassium hydroxide (KOH) to form water (H2O) and potassium perchlorate (KClO4) is: HClO4 + KOH → H2O + KClO4
The chemical equation for perchloric acid (HClO4) reacting with aqueous rubidium hydroxide (RbOH) is HClO4 + 2RbOH → RbClO4 + 2H2O. In this reaction, perchloric acid reacts with rubidium hydroxide to form rubidium perchlorate and water.