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i have done o.level in Pakistan.want to do my a.level.in UK could u guide me well please how at the age of 15 can admitte to a college and what is great britten law for teeneger who want to do their a level in UK.would u be able to deliver ur message to my email.www.bashir.masood@hotmail.com.thanks for paying good attention and thanks alot for everything.

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How much is 1 IB in grams?

1 IB (International Best) is equal to 0.45359237 grams.


How much oz is equal to 1 ib?

The answer depends on what you mean by an "ib".


Can you do Alevel from school or college?

yes.


Do you have an inventory in new Super Mario Brothers Wii?

yes, to view press 1 before entering alevel.


When was Ib Henrik Cavling born?

Ib Henrik Cavling was born on April 1, 1918, in Denmark.


How many ton are in ib?

Ummm....do you mean how many Ib's are in a ton? 1 ton=2000 pounds


How many ozs are in a 1 Ib?

16


In bjt small signal analysis in emitter stablization bias the circuit which have re unbypassed when trying to get zb the impedance why you divided vi by ib although that that both resistances beta r?

//you tell us and we'll both knowassuming that you have used h-parameter analysis for this ...Vb contains the Ib and the Ie terms which can be expressed ad Ie=(1+Hfe)Ibthen we haveVb=Hie*Ib + Re*Ie=Hie*Ib + Re(1+Hfe)Ib=Ib(Hie+(1+Hfe) Re)then we can findRi as Vb/Ib= Hie+(1+Hfe)*Rehope that helps....


How to calculate the current gain in darlington pair?

start at Ic'= Ic1+Ic2 Ib'=Ib1 Ic1=B1*Ib' Ie1=Ib2=Ib'(B1+1)=Ib'B1 + Ib' Ic' = Ib'*B1 + Ic2 Ic2= B2(Ib'B1+Ib') Ic' = Ib'B1 + Ib'B1B2 + Ib'B2 divide by Ib' Ic'/Ib'= current gain =B'=B1+B2+B1B2 note: calculations without resistance


How do you write square root of 7 plus i in the form of a plus ib?

It already is in the form a+ib. a = root 7, the b=1 (i.e 1 x i ).


How many grams are in 1 ib?

1 lb = 453.5924 grams


Why common collector amplifier current gain is equal to beta?

Actually the current gain is equal to Beta+1, not Beta. The current from/into the emitter is the sum of the current into/from the collector and base. Of course this assumes linear operation.For a proof: Ie + Ib + Ic = 0Ic = Beta * IbIe + Ib + Beta * Ib = 0Ie + (Beta + 1) * Ib = 0Ie = -(Beta + 1) * Ib