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The minimum bandwidth required for a multiplexed channel depends on the number of channels being multiplexed and the bandwidth of each individual channel. In general, the total minimum bandwidth needed is the sum of the bandwidths of all the channels being combined. For example, if you are multiplexing four channels, each requiring 1 MHz, a minimum bandwidth of 4 MHz would be necessary. Additionally, some multiplexing techniques may require guard bands to prevent interference, which would increase the total bandwidth requirement.
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Ten signals each requiring 4000 Hz are multiplexed on to a single channel using FDM How much minimum bandwidth is required for the multiplexed channel Assume that the guard bands are 400 Hz wide?
43600Hz (43.6KHz)
Find the minimum bandwidth for FDM five sources each requiring 400Hz 200Hz guard band per channel?
no of sources: 5 bandwidth required for each source= 400 Hz no of guard times= 5 bandwidth of each guard time = 200 Hz minimum bandwidth = 5 *400 + 5*200 Hz
Which analog modulation scheme requires minimum transmitted power and minimum channel bandwidth?
ssb modulation scheme
A digital signaling system is required to operate at 9600 bps If a signal element encodes a 8-bit word what is the minimum required bandwidth of the channel?
answer in www.ent.mrt.ac.lk/~ekulasek/cni/cni4-eck.ppt last slide
Given a bit rate of 1200 bps what is the minimum required bandwidth?
600 Hz
A digital data signaling system is requird to operate at 9600bps If a signal element encodes a 4-bit word what is the minimum required bandwidth of the channel?
C = 9600 = 2B*3 = 2B * 3 W = 1600 Hz
How do you calculate minimum bandwidth that a signal requires PSK?
To calculate the minimum bandwidth required for a Phase Shift Keying (PSK) signal, you can use the formula: ( B = \frac{R}{2} ) for binary PSK (BPSK), where ( B ) is the bandwidth and ( R ) is the data rate in bits per second. For higher-order PSK, such as QPSK or 8-PSK, the bandwidth can be calculated as ( B = \frac{R}{k} ), where ( k ) is the number of bits per symbol. Additionally, considering the required filtering and the Nyquist bandwidth, the actual bandwidth may be slightly wider to accommodate spectral shaping.
What is the minimum bandwidth required for an FSK signaling 3000 bauds per second with carrier frequencies separated by 4000 Hz?
7000 Hz
A QAM configuration uses four phases and one amplitude with a given bit rate of 1200 bps what is the minimum required bandwidth?
600
What is the required bandwidth of a low pass channel to transmit 1mbps by baseband communication?
The answer depends on the accuracy desired. a. The minimum bandwidth, a rough approximation, is B = bit rate /2, or 500 kHz. We need a low-pass channel with frequencies between 0 and 500 kHz. b. A better result can be achieved by using the first and the third harmonics with the required bandwidth B = 3 × 500 kHz = 1.5 MHz. c. A still better result can be achieved by using the first, third, and fifth harmonics with B = 5 × 500 kHz = 2.5 MHz
Four signals each requiring 9600 bps what is the minimum required bandwidth?
38,400 bps... But how old is this question that the speed is so insanely slow?
What is the minimum bandwidth required for an FSK signal transmitting 3000 bauds per second with carrier frequencies separated by 4000 Hz?
7000 Hz
