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A solution that does not contain enough solute?
A solution that only contains a small amount of solute, is a dilute or very dilute solution.
What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
HOW TO 0.1N NaOH solution preparation?
To prepare a 0.1N NaOH solution, dissolve 4g of sodium hydroxide (NaOH) pellets in enough water to make 1 liter of solution. Use a volumetric flask to accurately measure the final volume. Remember to handle NaOH with caution as it is a caustic substance.
How do you determine the molarity of a solution containing 18.2g C6H12O6and enough water to reach 6.3L?
Moles of solute ---------------- Liters of solution So, convert your grams to moles by dividing by the molar mass (add together the atomic masses of the solution) and then that will give you your moles. Divide that number by your 6.3 Liters. That number is your molarity.
What is the molarity of a solution formed by mixing 20.0 g sulfuric acid with enough water to make 500.0 mL of solution?
To find the molarity, start by converting grams of sulfuric acid to moles. the molar mass of sulfuric acid (H2SO4) is 98.08 g/mol. Divide the moles by the volume in liters (500.0 mL = 0.5 L) to get the molarity. Molarity = moles/volume (L).
Calculate the molar it’s oh a solution that contains 15.7 of CaCO3 dissolved in enough water to make 275mL of solution?
0.570 M (note the capital M, this is molarity.)
What is the molarity of 20.2 g of potassium nitrate in enough water to make 250.0 mL of solution?
To find the molarity, first calculate the number of moles of potassium nitrate using its molar mass (101.1 g/mol). This comes out to 0.2 moles. Then, divide the moles by the volume of the solution in liters (0.250 L) to get the molarity, which is 0.8 M.
2.431 g of h2c2o4 x 2h2o was obtained and dissolved in enough dI water to form 250.0 ml of solution what is the concentration of the resulting of h2c2o4 solution?
Molarity (concentration ) = moles of solute/Liters of solution 250.0 ml = 0.250 liters 2.431 grams H2C2O4 * 2H2O ( 1mole cpd/ 126.068 grams) = 0.01928 moles H2C2O4 * 2H2O Molarity = 0.01928 moles cpd/0.250 liters = 0.07712 Molarity
How do you solve freezing point depression problems when given only the molarity?
Calculating the freezing point depression of a solvent requires three pieces of information: 1) the molal freezing point depression of that solvent; 2) the molality of the solution; 3) the number of distinct entities produced in solution per molecular formula unit of solute. Hopefully you meant molality instead of molarity (if the solvent is water and it's a dilute solution, assuming that molality = molarity isn't a bad approximation). I suspect you've been told what 1 and 3 are (or been given enough information to figure them out) but simply didn't mention it; otherwise you're pretty much boned.
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
What is the molarity of the solution formed by mixing 0.20 mol of sodium hydroxide with enough water to make 150 ml of solution?
To calculate the molarity of the solution, first convert the volume to liters (150 mL = 0.150 L). Then, divide the moles of solute (0.20 mol NaOH) by the volume of solution in liters to get the molarity. Molarity = 0.20 mol / 0.150 L = 1.33 M.
